 Replace each cell in a dataframe by the value of a dict inside each cell pandas
By : duur laiti
Date : March 29 2020, 07:55 AM
this one helps. Here is my dataframe : , How about this: code :
df2 = df2.apply(lambda axis: [axis[0]] + [x['tag_name'] for x in axis[1:]], axis=1)
df2 = df2.apply(lambda axis: [x['tag_name'] if type(x) == dict else x for x in axis], axis=1)
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how to replace a cell in a pandas dataframe
By : D Indra
Date : March 29 2020, 07:55 AM
it fixes the issue After forming the below python pandas dataframe (for example) , Hope you are looking for where for conditional replacement i.e code :
def wow(x):
return x ** 10
df['new'] = df['Age'].where(~(df['Name'] == 'Alex'),wow(df['Age']))
Name Age new
0 Alex 10 10000000000
1 Bob 12 12
2 Clarke 13 13
3 Alex 15 576650390625df['new'] = df['PEER_SRC_IP'].apply(lookup_netelement)
def wow(x,y):
return '{} {}'.format(x,y)
df.apply(lambda x : wow(x['Name'],x['Age']),1)
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I need to replace one cell with another in pandas dataframe
By : user2444134
Date : March 29 2020, 07:55 AM
hope this fix your issue I want to replace one cell of a row with another cell of same row in pandas data frame enter image description here , This can solve your specific problem: code :
df.iloc[4,3] = df.iloc[4,2]
df.iloc[4,2] = df.iloc[4,1]
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 Python Pandas replace a cell containing a string with its above cell
By : henryalgnp
Date : March 29 2020, 07:55 AM
hop of those help? The general structure for these kind of problems is df.loc[cond, col] = ... Using @meW's setup, code :
df = pd.DataFrame({'col': ['Elephant', 'Grass', 'Parameter', 'Root']})
df.loc[df.col.eq('Parameter'), 'col'] = df.col.shift(1)
col
0 Elephant
1 Grass
2 Grass
3 Root
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Pandas: replace empty cell to 0
By : Danilo Lopez
Date : March 29 2020, 07:55 AM
may help you . You are creating a copy of the dataframe but the original one is not keeping the changes, you need to specify "inplace=True" if you want the dataframe to persist the changes
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code :
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