I want to show all image preview but whenever I upload a new one the old one is gone

I want to show all image preview but whenever I upload a new one the old one is gone

By : vpa
Date : January 12 2021, 07:00 PM
may help you . The issue is in the state set or structure, depending on the point of view.
This is your initial state:
code :
state = {
  form: {
    frontDesign: [],
    backDesign: [],
    leftDesign: [],
    rightDesign: []
    this.setState(state => ({
      form: {
        frontDesign: [reader.result]
  this.setState(state => ({
    form: {
      frontDesign: [reader.result]

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How to show upload image preview using jquery before form submit in a div

How to show upload image preview using jquery before form submit in a div

By : Topher Bear
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You need to loop through the files array from the multiple input and use the FileReader API on each.
I've set up the HTML like this:
code :
​<input type="file" multiple="true" id="files" />
<input type="submit" id="go"/>
<div id="images"></div>​​​​​​​​​​​​​​​​​​​​​​
// set up variables
var reader = new FileReader(),
    numFiles = 0,

// use the FileReader to read image i
function readFile() {

// define function to be run when the File
// reader has finished reading the file
reader.onloadend = function(e) {

    // make an image and append it to the div
    var image = $('<img>').attr('src', e.target.result);

    // if there are more files run the file reader again
    if (i < numFiles) {

$('#go').click(function() {

    imageFiles = document.getElementById('files').files
    // get the number of files
    numFiles = imageFiles.length;

Show an image preview before upload

Show an image preview before upload

By : JPenney
Date : March 29 2020, 07:55 AM
wish help you to fix your issue HTML5 comes with File API spec, which allows you to create applications that let the user interact with files locally; That means you can load files and render them in the browser without actually having to upload the files. Part of the File API is the FileReader interface which lets web applications asynchronously read the contents of files .
Here's a quick example that makes use of the FileReader class to read an image as DataURL and renders a thumbnail by setting the src attribute of an image tag to a data URL:
code :
<input type="file" id="files" />
<img id="image" />
document.getElementById("files").onchange = function () {
    var reader = new FileReader();

    reader.onload = function (e) {
        // get loaded data and render thumbnail.
        document.getElementById("image").src = e.target.result;

    // read the image file as a data URL.
function handleFileSelect(evt) {
    var files = evt.target.files;

    // Loop through the FileList and render image files as thumbnails.
    for (var i = 0, f; f = files[i]; i++) {

      // Only process image files.
      if (!f.type.match('image.*')) {

      var reader = new FileReader();

      // Closure to capture the file information.
      reader.onload = (function(theFile) {
        return function(e) {
          // Render thumbnail.
          var span = document.createElement('span');
          span.innerHTML = 
            '<img style="height: 75px; border: 1px solid #000; margin: 5px" src="', 
            '" title="', escape(theFile.name), 
          document.getElementById('list').insertBefore(span, null);

      // Read in the image file as a data URL.

  document.getElementById('files').addEventListener('change', handleFileSelect, false);
<input type="file" id="files" multiple />
<output id="list"></output>
Show preview image, upload on submit form

Show preview image, upload on submit form

By : George Ellams
Date : March 29 2020, 07:55 AM
wish helps you I'm working with the jquery plugin transloadit to upload images to my amazon s3 bucket. , Try filereader
code :
function readURL(input) {
    if (input.files && input.files[0]) {
        var reader = new FileReader();

        reader.onload = function (e) {
            $('#blah').attr('src', e.target.result);


How to show image preview before Upload?

How to show image preview before Upload?

By : cguercio
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You can use URL.createObjectURL() to create a Blob URL of uploaded image.
Adjusted html to
as appended parent element instead of element.
code :
$(document).on('click', '.close', function() {

document.getElementById("uploadBtn").onchange = function() {
  document.getElementById("uploadFile").value = this.value;

document.getElementById('uploadBtn').onchange = uploadOnChange;

function uploadOnChange() {
  var filename = this.value;
  var lastIndex = filename.lastIndexOf("\\");
  if (lastIndex >= 0) {
    filename = filename.substring(lastIndex + 1);
  var files = $('#uploadBtn')[0].files;
  for (var i = 0; i < files.length; i++) {
    (function(i) {
      $("#upload_prev").append('<div><br><div class="col-md-10"><span class="uploadFiles">' + '<a href="">' + files[i].name + '</a>' + '</span></div><div class="col-md-2"><p class="close" style="font-size: 13pt;">削除</p><br></div></div>');
      $("#upload_prev a:contains(" + files[i].name + ")")
        .on("click", function(e) {
          var close = $(this).closest("div")
          if (!$(this).closest("div")
              $("<img>", {
                src: URL.createObjectURL(files[i])

  document.getElementById('filename').value = filename;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input id="uploadBtn" type="file" class="upload" multiple="multiple" accept="image/*" name="browsefile" style="display: none !important;" />

<input type="button" value="ファイル追加" onclick="document.getElementById('uploadBtn').click();" style="float: right;" />

<input id="filename" type="hidden" />
<div id="upload_prev"></div>
<div style="clear:both;"></div>
Show preview of Image and upload file with AngularJs

Show preview of Image and upload file with AngularJs

By : Mitchell
Date : March 29 2020, 07:55 AM
it helps some times You have to convert the file data that is read to Base 64 string format. Then you can use that base 64 data to show the image.
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