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the collatz func in automate boring stuff with python


the collatz func in automate boring stuff with python

By : user3100273
Date : January 12 2021, 01:40 AM
it fixes the issue Your mistake is int(input("enter:")), because you are passing in a string into your function collatz(number), without converting it into int.
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Making a collatz program automate the boring stuff

Making a collatz program automate the boring stuff


By : user41543
Date : March 29 2020, 07:55 AM
I wish this help you I'm trying to write a Collatz program using the guidelines from a project found at the end of chapter 3 of Automate the Boring Stuff with Python. I'm using python 3.4.0. Following is the project outline:
code :
def collatz(number):

    if number % 2 == 0:
        print(number // 2)
        return number // 2

    elif number % 2 == 1:
        result = 3 * number + 1
        print(result)
        return result

n = input("Give me a number: ")
while n != 1:
    n = collatz(int(n))
Give me a number: 3
10
5
16
8
4
2
1

Give me a number: 11
34
17
52
26
13
40
20
10
5
16
8
4
2
1
Dictionary from Automate the boring stuff with Python

Dictionary from Automate the boring stuff with Python


By : Preeti Jindal
Date : March 29 2020, 07:55 AM
like below fixes the issue This program is from "Automate the boring stuff with python". I am not able to understand, what tells the program to take "name" as Key and "bday" as Value , we can directly add key , value to dictionary
For reference:
code :
d = {}
print(d)
d['Name']='1st April';
print(d)
{}
{'Name': '1st April'}
Automate the Boring Stuff Collatz Project

Automate the Boring Stuff Collatz Project


By : Mr_five
Date : March 29 2020, 07:55 AM
I wish this helpful for you The recursive case doesn't return anything, so control reaches the end of the function as the call stack resolves (Python functions implicitly return None, hence your error). Change the line:
code :
integercheck(input())
return integercheck(input())
def collatz(n):
    while n > 1:
        if n % 2 == 0:
            n //= 2
        else:
            n = 3 * n + 1

        yield n

def get_int(prompt="Enter a number: ", 
            err="Error: Input needs to be a number."):
    while True:
        try:
            return int(input(prompt))
        except ValueError:
            print(err)

if __name__ == "__main__":
    for step in collatz(get_int()):
        print(step)
Automate the boring stuff with Python: Mad Libs

Automate the boring stuff with Python: Mad Libs


By : user3726205
Date : March 29 2020, 07:55 AM
To fix this issue The problem in your code is that you are not checking your return values.
code :
for i in range(amount):
    try:
        if result == 'NOUN':
            print('Enter a noun:')
            k = input()
            mad_regex.sub(k, content, 1)
            content = mad_regex.sub(k, content, 1)
            search = mad_regex.search(content)  # This returns None when it doesn't match
            result = search.group() # Search is now None, and you get your exception
python - a collatz program automate the boring stuff

python - a collatz program automate the boring stuff


By : Abhik De
Date : March 29 2020, 07:55 AM
like below fixes the issue You are not updating number in your while loop so you are stuck in an infinite loop.
You should assign return value of collatz to number back, to update number.
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