Trying to define a promise.all

Trying to define a promise.all

By : user3100239
Date : January 12 2021, 01:40 AM
I wish did fix the issue. The issue with the code, as @Bergi said, was that the ".then" and ".catch" callbacks are called asynchronously and as a consequence of this, "fullArray" wasn't even filled when "resolve()" was called even when it was outside of the loop. To solve this, i simply added "resolve()" inside of the promise that finishes last, to do this, i simply added a "counter" binding that has the value of the length of the "promises" array, and is reduced by 1 every time ".then" was called on a promise and when this "counter" equals 0, it calls "resolve()".
But that only solves the problem of filling the "fullArray" with the promises, not the issue of those promises being ordered correctly by the order they were called, to solve this i simply enumerated them in the array with the "i" binding of the loop, the end result was this:
code :
function Promise_all(promises) {
  return new Promise((resolve, reject) => {
    if(promises.length == 0) resolve(promises);
    let fullArray = [],
        counter = promises.length;

    for(let i=0; i< promises.length ; i++){
        .then(x => {
           fullArray[i] = x;
           if(counter == 0) resolve(fullArray)})
        .catch(reason => reject(new Error(reason)));

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Define empty Bluebird promise like in Q

Define empty Bluebird promise like in Q

By : Narek Anatolyan
Date : March 29 2020, 07:55 AM
Hope this helps With Q I can define a new promise with:
code :
var resolver = Promise.defer();
setTimeout(function() {
    resolver.resolve(something); // Resolve the value
}, 5000);
return resolver.promise;
return new Promise(function(resolve, reject) {
    // Your code
var gitControl = Promise.promisifyAll(Main.gitControl);
var promises = [];
promises.push(gitControl.gitAddAsync(fileObj.filename, updateIndex));
return promises;
Define an empty Q.Promise<void>

Define an empty Q.Promise<void>

By : Airazel Perlas Capun
Date : March 29 2020, 07:55 AM
I hope this helps . I am new to Q and promises. I have a simple interface that I want to implement. To focus the question, I simplified the interface and its implemenration: , Importing Q worked:
code :
import * as Q from "q";
In TypeScript, what is the best way to define a function that can return either Promise<T> or Promise<T[]>?

In TypeScript, what is the best way to define a function that can return either Promise<T> or Promise<T[]>?

By : Aistis Matulis
Date : March 29 2020, 07:55 AM
Does that help I'm just starting with TypeScript and I ran across a situation in which the type definitions for a library I'm using is wrong. In my case, the library is Massive,js, and here are the type definitions. , You can define multiple types.
code :
interface Table<T> {
    // other functions omitted for simplicity
    save(data: object): Promise<T | T[]>;
    insert(data: object): Promise<T | T[]>;
    update(dataOrCriteria: object, changesMap?: object): Promise<T | T[]>;
Define Promise As ES6 Class Method

Define Promise As ES6 Class Method

By : JustMeDaFaq
Date : March 29 2020, 07:55 AM
will help you Promises are just an object returned from a function — whether it be a method or not doesn't matter. Try this:
how axios promise define errors

how axios promise define errors

By : Hailu
Date : March 29 2020, 07:55 AM
it helps some times My understanding is that if any sort of networking issue occurs or if an error code is responded from the server then the promise is rejected.
An error code from the server is either a client error (4XX) or server error (5XX). Status code definitions.
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