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The conditional operator is not allowing the program to terminate


The conditional operator is not allowing the program to terminate

By : Felipe Antonio Kraus
Date : January 12 2021, 01:40 AM
Any of those help It stuck because, if the condition ((*beg)%2 == 0 && (beg < nums.end()) is true, the iterator will not increment for checking further. You have only setting i=0. You should increment the iterator as well.
You can use comma operator for this:
code :
while (beg != nums.end()  && *beg > 0)
{
    (*beg) % 2 == 0  ? (beg++, i): (*beg = 2 * (*beg) , beg++, ++i );
}
#include <iostream>
#include <vector>

int main()
{
    std::vector<int> nums = { 1,2,3,4,5,6,7,8,9 };
    int i{0};
    auto beg = nums.begin();

    while (beg != nums.end()  && *beg > 0)
    {
        (*beg) % 2 == 0  ? (beg++, i): (*beg = 2 * (*beg) , beg++, ++i );
    }
    for (const int ele : nums)
            std::cout << ele << " ";
    std::cout << "\ncount: " << i << "\n";
}
2 2 6 4 10 6 14 8 18 
count: 5


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Allowing JTable to be edited by program only, but allowing users able to copy data from it

Allowing JTable to be edited by program only, but allowing users able to copy data from it


By : Gurleen
Date : March 29 2020, 07:55 AM
I wish did fix the issue. In you need to set the selection properties of your table to true, like below. You also have to make sure that the isCellEditable method is overridden and set to false, the AbstractTableModel class does this by default.
code :
  final JTable table = new JTable(new AbstractTableModel() {

        @Override
        public Object getValueAt(int r, int c) {
            return data[r][c];
        }

        @Override
        public int getRowCount() {
            return data.length;
        }

        @Override
        public int getColumnCount() {
            return data[1].length;
        }

    });

    table.setRowSelectionAllowed(true);
    table.setColumnSelectionAllowed(true);
    table.setCellSelectionEnabled(true);
Why is the use of the conditional operator giving the warning "pointer/integer type mismatch " in my program?

Why is the use of the conditional operator giving the warning "pointer/integer type mismatch " in my program?


By : xmaple
Date : March 29 2020, 07:55 AM
With these it helps I suspect that #include is not included, which means strerror() has an implicit function declaration generated for it which returns an int.
This code (http://ideone.com/6BckJx):
code :
#include <stdio.h>
#include <errno.h>

int main()
{
    printf("%d : %s\n", errno, (errno==0)?"no error":strerror(errno));
    return 0;
}
prog.c: In function ‘main’:
prog.c:6:5: error: implicit declaration of function ‘strerror’ 
    [-Werror=implicit-function-declaration]
prog.c:6:53: error: pointer/integer type mismatch in conditional expression
    [-Werror]
cc1: all warnings being treated as errors
How to create empty-conditional operator for collections similar to null-conditional operator?

How to create empty-conditional operator for collections similar to null-conditional operator?


By : sahid khan
Date : March 29 2020, 07:55 AM
I wish this helpful for you IMHO, the "most elegent" solution is to re-write MinBy to make it in to a MinByOrDefault
code :
public static TSource MinByOrDefault<TSource, TKey>(this IEnumerable<TSource> source,
    Func<TSource, TKey> selector)
{
    return source.MinByOrDefault(selector, Comparer<TKey>.Default);
}

public static TSource MinByOrDefault<TSource, TKey>(this IEnumerable<TSource> source,
    Func<TSource, TKey> selector, IComparer<TKey> comparer)
{
    if (source == null) throw new ArgumentNullException("source");
    if (selector == null) throw new ArgumentNullException("selector");
    if (comparer == null) throw new ArgumentNullException("comparer");
    using (var sourceIterator = source.GetEnumerator())
    {
        if (!sourceIterator.MoveNext())
        {
            return default(TSource); //This is the only line changed.
        }
        var min = sourceIterator.Current;
        var minKey = selector(min);
        while (sourceIterator.MoveNext())
        {
            var candidate = sourceIterator.Current;
            var candidateProjected = selector(candidate);
            if (comparer.Compare(candidateProjected, minKey) < 0)
            {
                min = candidate;
                minKey = candidateProjected;
            }
        }
        return min;
    }
}
Perl 6 '^=' operator doesn't produce a result, causing program to never terminate

Perl 6 '^=' operator doesn't produce a result, causing program to never terminate


By : user1481550
Date : March 29 2020, 07:55 AM
I hope this helps .
There are several infix operators with ^ in them, all of them mean exclusive-or in some form.
code :
so     1 == 1 ^ 2; # True
so     2 == 1 ^ 2; # True
so    42 == 1 ^ 2; # False
so 1 ^ 2 == 1 ^ 2; # False

my $v = 1 ^ 2;
so 1 == $v; # True
say ( 0 ^^ 42 ^^ Nil );
42

say ( !say(1) ^^ !say(2) ^^ -1 but False );
1
2
-1

say ( say(1) ^^ say(2) ^^ say(3) );
1
2
Nil
say (0b10101010 +^ 0b10100000).base: 2; # 1010

say 1.5 +^ 2; # 3
say 'aa' ~^ 'US'; # 42
my $k = 1;
my $v = $k ^ 24;
say $v; # one(1, 24);

$k = 2;
say $v; # one(2, 24);
How does the conditional operator change the value of the variable b in the program below?

How does the conditional operator change the value of the variable b in the program below?


By : user2190495
Date : March 29 2020, 07:55 AM
hope this fix your issue , Let's look at this row:
code :
*((a+1 == 1) ? &b : &a) = a ? b : c;
*(1 ? &b : &a) = a ? b : c;
*(&b) = a ? b : c;
*(&b) = c;
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