Spring Data JPA query , filter ? search engine ? JPQL?

Spring Data JPA query , filter ? search engine ? JPQL?

By : Roberto Torrres
Date : January 12 2021, 01:40 AM
help you fix your problem The simplest way to provide a dynamic search with Spring Boot is to use specifications.
Enable search by specification in your repository class :
code :
public interface FatherRepository extends JpaRepository<Father, Long>, JpaSpecificationExecutor<Father> {}
public class FatherSpecifications {
    public static Specification<Father> hasBirthdate(LocalDate birthdate) {
        return (father, cq, cb) -> Optional.ofNullable(birthdate).map(b -> cb.equal(father.get("birthdate"), b)).orElse(null);

    public static Specification<Father> firstnameLike(String firstname) {
        return (father, cq, cb) -> Optional.ofNullable(firstname).map(f -> cb.like(father.get("firstname"), "%" + f + "%")).orElse(null);

    public static Specification<Father> surnameLike(String surname) {
        return (father, cq, cb) -> Optional.ofNullable(surname).map(s -> cb.like(father.get("surname"), "%" + s + "%")).orElse(null);
List<Father> fathers = fatherRepository.findAll(Specification.where(FatherSpecifications.hasBirthdate(birthdate)).and(FatherSpecifications.firstnameLike(firstname)).and(FatherSpecifications.surnameLike(surname)));

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Spring Data Hibernate JPQL Aggregate Query

Spring Data Hibernate JPQL Aggregate Query

By : user7423507
Date : March 29 2020, 07:55 AM
this one helps. I have a Spring Data implementation with an entity , You must add a JoinColumn to establish the relationship:
code :
@ManyToOne(optional = false)
private Account account;
Spring data JPA JPQL query on child property

Spring data JPA JPQL query on child property

By : Luca1990
Date : March 29 2020, 07:55 AM
will help you I am using spring-data jpa. When querying parent object with child object property,I was expecting parent with aggregated child objects.I have OneToMany relation between User and Phone. Just typing some part of code. , Try:
code :
@Query(select distinct u from User u inner join u.phone ph where ph.active=:active)
Page<User> getAllUsers(@Param("active") int active);
Spring Data JPA (JPQL) problem: Using TIMESTAMPDIFF function in JPA query

Spring Data JPA (JPQL) problem: Using TIMESTAMPDIFF function in JPA query

By : user2139959
Date : March 29 2020, 07:55 AM
will help you Actually, there is no TIMESTAMPDIFF in JPQL.
Reference: timestampdiff equivalent in JPQL (without using criteria)
Spring Data JPA - ManyToMany - JPQL - @Query formation in Repository

Spring Data JPA - ManyToMany - JPQL - @Query formation in Repository

By : user2544788
Date : March 29 2020, 07:55 AM
Any of those help I have resolved the issue. Since the entity classes have been generated using Eclipse plugins, so the class for customer_product was not been generated. So I manually generated it and used the query. So the final code is:
code :
@NamedQuery(name="CustomerProduct.findAll", query="SELECT c FROM CustomerProduct c")
public class CustomerProduct implements Serializable {
    private static final long serialVersionUID = 1L;

    private Integer id;

    private Integer customerId;

    private Integer productId;
@Query("select new com.arindam.springjpa.springdatajpaexamples.vo.CustomerProductAddressDetailsVO(cp.id, c.customerName, a.fullAddress, p.productName) from Customer c, Address a, Product p, CustomerProduct cp "
            + "where c.address.addressId=a.addressId and cp.productId=p.productId and cp.customerId=c.id")
    List<CustomerProductAddressDetailsVO> findAllCustomerAddressProductDetails();
Cannot writing JPQL query with subquery in FROM clause - Spring Data Jpa - Hibernate

Cannot writing JPQL query with subquery in FROM clause - Spring Data Jpa - Hibernate

By : user3708308
Date : March 29 2020, 07:55 AM
like below fixes the issue It's not possible in jpql. Take a look at the documentation. It says:
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