Dynamically generated class that implements IEnumerator<T> GetEnumerator() and IEnumerator IEnumerable.GetEnumerat
By : Roberta Macedo
Date : March 29 2020, 07:55 AM
around this issue I have a problem with Reflection.Emit. I want to have dynamically created class, that has simple implementation of ICollection. All methods I've defined fine, instead of next two: public IEnumerator GetEnumerator() & IEnumerator IEnumerable.GetEnumerator() Next code shows what I want to be in my dynamic class: , Answer is next define of the method code :
MethodBuilder myMethod = myType.DefineMethod("System.Collections.IEnumerable.GetEnumerator",
MethodAttributes.Private | MethodAttributes.HideBySig |
MethodAttributes.NewSlot | MethodAttributes.Virtual |
MethodAttributes.Final);
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Relation between IEnumerator<T>.Current and IEnumerator.Current and Why IEnumerator<T> implements IDisposabl
By : user3128478
Date : March 29 2020, 07:55 AM
Any of those help There are several cases where it's useful that IEnumerator inherits from IDisposable. For example take File.ReadLines() which needs to keep open a FileStream, which is an unmanaged resource. code :
IEnumerator<int> MyIt()
{
try
{
yield return 1;
}
finally
{
//Do Something
}
}
T Current//Implicit interface implementation
{
get
{
return something;
}
}
object IEnumerator.Current{get{return Current;}}
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Can't implement both GetEnumerator return IEnumerator AND IEnumerator<T> when implementing ICollection<T>
By : Dipanshu Mahajan
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I'm writing a simple collection class that implements ICollection . Everything basically works except if I add a IEnumerator GetEnumerator() method it complains I don't have an IEnumerator GetEnumerator() method. And vice versa. I'm not allowed to have both since they differ only in return type, so I'm really quite confused as to what the compiler wants from me. , Implement them explicitly: code :
IEnumerator IEnumerable.GetEnumerator() {
}
IEnumerator<T> IEnumerable<T>.GetEnumerator() {
}
// etc.
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How do i convert this Func<SampleExpression,IEnumerator<string>,bool>> to Func<SampleExpression,bool&g
By : konhadi happy
Date : March 29 2020, 07:55 AM
I wish this help you The expression compilation seems weird to me too, but to actually answer your question... You can wrap the compiled Func like so: code :
Func<SampleExpression, bool> lBind = (SampleExpression token) => l(token, lstConstant.GetEnumerator());
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Spring4d: Spring.Collections.IEnumerator and System.IEnumerator
By : Cillian Kennedy
Date : March 29 2020, 07:55 AM
will be helpful for those in need Write it yourself (FWIW I would prefer opposite parameter order but I kept it like that since the signature of TStringHelper.Join): code :
function StringJoin(const separator: string; const values: Spring.Collections.IEnumerable<string>): string; overload;
var
e: Spring.Collections.IEnumerator<string>;
begin
e := values.GetEnumerator;
if not e.MoveNext then
Exit('');
Result := e.Current;
while e.MoveNext do
Result := Result + separator + e.Current;
end;
StringJoin(',', TEnumerable.Distinct<string>(Modules, TStringComparer.OrdinalIgnoreCase))
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