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I have a regex statement to pull all numbers out of a text file, but it only finds 77 out of the 81 numbers in the file


I have a regex statement to pull all numbers out of a text file, but it only finds 77 out of the 81 numbers in the file

By : user3099877
Date : January 11 2021, 05:14 PM
hop of those help? You regex is working as you wrote it, and it is finding a pattern matching:
a negative sign (optional) one digit a decimal point (.) exactly 16 digits after the decimal point.
code :


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Batch File - Error in FOR / IF statement with numbers and text

Batch File - Error in FOR / IF statement with numbers and text


By : user3660042
Date : March 29 2020, 07:55 AM
help you fix your problem What changed is that with the original code, SET SELECTION=%c% & EXIT /B is executed IF /i #%c%==#%%I.
With your modified code, SET SELECTION=%c% is executed IF /i #%c%==#%%Iand the exit is executed regardless.
code :
IF %A%==1 FOR %%I IN (1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 A B C D) DO IF /i #%c%==#%%I (
    SET SELECTION=%c%
    EXIT /B
    )
Python regex a binary file text file - how to use a range of numbers and word boundry?

Python regex a binary file text file - how to use a range of numbers and word boundry?


By : Vince Matinde
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I have a text file that requires me to read it in binary and write out in binary. No problem. I need to mask out Social Security Numbers with Xs, pretty easy normally: , You might try:
code :
import re

rx = re.compile(r'\b\d{3}-\d{2}-\d{4}\b')

with open("test.txt", "rb") as fr, open("test2.txt", "wb+") as fp:
    repl = rx.sub('XXX-XX-XXXX', fr.read())
    fp.write(repl)
Program that finds and prints all prime numbers 1-100 to a file

Program that finds and prints all prime numbers 1-100 to a file


By : Hooi Ling
Date : March 29 2020, 07:55 AM
This might help you Since every number is divisible by the number itself, you are getting false from the function. Just change the loop condition from i <= num1 to i < num1.
code :
for (i = 2; i < num1; i++) {
    if (num1 % i == 0) {
        return false;
    }
}
Find phone numbers regex in text file using batch

Find phone numbers regex in text file using batch


By : pwhite
Date : March 29 2020, 07:55 AM
will be helpful for those in need This is my first batch file attempt. I need to extract all the phone numbers from a text file and store them all in a separate file. Any string that has 10 digits is a phone number. , Using your RegEx you could leverage PowerShell from your batch file:
code :
@PowerShell "GC 'print.txt'|%%{[Regex]::Matches($_,'\d{10}')}|%%{$_.Value}">"newfile.txt"
How to reverse order numbers in a text file then write the reversed numbers back into the text file

How to reverse order numbers in a text file then write the reversed numbers back into the text file


By : user3174408
Date : March 29 2020, 07:55 AM
this one helps. Alright, to read a sequence of numbers and then write them back out in reverse order, you simply need to read the values into an array, keeping track of how many you read, close the file opened for reading, reopen the file for writing, then write the values back out to the file in reverse order.
We will leave reading an unknown number of values from the file and dynamically allocating storage for another day. We will presume for now that you have less than 256 values to read (adjust as necessary). Avoid using magic-numbers in your code, so if you need a constant to size your array, #define one (or more),
code :
#include <stdio.h>

#define MAXI 256    /* if you need a constant, #define one (or more) */
int main (int argc, char **argv) {

    int arr[MAXI] = {0};    /* array for storing values */
    size_t n = 0;           /* counter for number stored */
    /* use filename provided as 1st argument (stdin by default) */
    FILE *fp = argc > 1 ? fopen (argv[1], "r") : stdin;

    if (!fp) {  /* validate file open for reading */
        perror ("file open failed");
        return 1;
    }
    /* protect your array bounds, and read/validate 1 int per iteration */
    while (n < MAXI && fscanf (fp, "%d", &arr[n]) == 1)
        n++;    /* on success, increment counter */

    if (fp != stdin)   /* close file if not stdin */
        fclose (fp);
    /* open file for writing (stdout by default) */
    fp = argc > 1 ? fopen (argv[1], "w") : stdout;

    if (!fp) {  /* validate file open for writing */
        perror ("file open failed");
        return 1;
    }

    while (n--) /* write array in reverse order to file */
        fprintf (fp, "%d\n", arr[n]);

    if (fp != stdout)           /* close file if not stdout */
        if (fclose(fp) == -1)   /* always validate close-after-write */
            perror ("fclose-fp");
}
#include <stdio.h>

#define MAXI 256    /* if you need a constant, #define one (or more) */

int main (int argc, char **argv) {

    int arr[MAXI] = {0};    /* array for storing values */
    size_t n = 0;           /* counter for number stored */
    /* use filename provided as 1st argument (stdin by default) */
    FILE *fp = argc > 1 ? fopen (argv[1], "r") : stdin;

    if (!fp) {  /* validate file open for reading */
        perror ("file open failed");
        return 1;
    }

    /* protect your array bounds, and read/validate 1 int per iteration */
    while (n < MAXI && fscanf (fp, "%d", &arr[n]) == 1)
        n++;    /* on success, increment counter */

    if (fp != stdin)   /* close file if not stdin */
        fclose (fp);

    /* open file for writing (stdout by default) */
    fp = argc > 1 ? fopen (argv[1], "w") : stdout;

    if (!fp) {  /* validate file open for writing */
        perror ("file open failed");
        return 1;
    }

    while (n--) /* write array in reverse order to file */
        fprintf (fp, "%d\n", arr[n]);

    if (fp != stdout)           /* close file if not stdout */
        if (fclose(fp) == -1)   /* always validate close-after-write */
            perror ("fclose-fp");
}
$ cat dat/10intordered.txt
1
2
3
4
5
6
7
8
9
10
$ ./bin/revfile < dat/10intordered.txt
10
9
8
7
6
5
4
3
2
1
#include <stdio.h>

#define MAXI 256    /* if you need a constant, #define one (or more) */

int main (int argc, char **argv) {

    int arr[MAXI] = {0};    /* array for storing values */
    int n = 0;              /* counter for number stored */
    /* use filename provided as 1st argument (stdin by default) */
    FILE *fp = argc > 1 ? fopen (argv[1], "r") : stdin;

    if (!fp) {  /* validate file open for reading */
        perror ("file open failed");
        return 1;
    }

    puts ("reading file:");
    /* protect your array bounds, and read/validate 1 int per iteration */
    while (n < MAXI && fscanf (fp, "%d", &arr[n]) == 1) {
        printf ("  arr[%3d] : %d\n", n, arr[n]);
        n++;    /* on success, increment counter */
    }
    printf ("read of %d integers -- complete.\n", n);

    if (fp != stdin)   /* close file if not stdin */
        fclose (fp);

    /* open file for writing (stdout by default) */
    fp = argc > 1 ? fopen (argv[1], "w") : stdout;

    if (!fp) {  /* validate file open for writing */
        perror ("file open failed");
        return 1;
    }

    puts ("\nwriting values to file:");
    /* loop writing indexes out from n-1 to 0 */
    for (int i = n-1; i >= 0; i--) {
        printf ("  arr[%3d] : %d\n", i, arr[i]);
        fprintf (fp, "%d\n", arr[i]);
    }
    printf ("write of %d integers -- complete.\n", n);

    if (fp != stdout)           /* close file if not stdout */
        if (fclose(fp) == -1)   /* always validate close-after-write */
            perror ("fclose-fp");
}
$ cat dat/10i.txt
1
2
3
4
5
6
7
8
9
10
$./bin/revfile2 dat/10i.txt
reading file:
  arr[  0] : 1
  arr[  1] : 2
  arr[  2] : 3
  arr[  3] : 4
  arr[  4] : 5
  arr[  5] : 6
  arr[  6] : 7
  arr[  7] : 8
  arr[  8] : 9
  arr[  9] : 10
read of 10 integers -- complete.

writing values to file:
  arr[  9] : 10
  arr[  8] : 9
  arr[  7] : 8
  arr[  6] : 7
  arr[  5] : 6
  arr[  4] : 5
  arr[  3] : 4
  arr[  2] : 3
  arr[  1] : 2
  arr[  0] : 1
write of 10 integers -- complete.
$ cat dat/10i.txt
10
9
8
7
6
5
4
3
2
1
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