I hope this helps you . I'm having issues when i need to do a count (or aggregation) in recursion problems, for eg. in this problem where i'm trying to divide 2 integers w/o using multiplication, division and mod operator. , One possible problem is related to this logic: code :
if(dividend > origDivisor):
self.helper(dividend, origDivisor, origDivisor, count)
else:
return count
if(dividend > origDivisor):
return self.helper(dividend, origDivisor, origDivisor, count)
return count
def divide(dividend, divisor):
quotient = divide_recursive(dividend, divisor)
return quotient
def divide_recursive(dividend, divisor, count=0):
if dividend >= divisor:
return divide_recursive(dividend  divisor, divisor, count + 1)
return count
print(divide(125, 5))
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Why is my solution on LeetCode not working (recursion, python)?
By : lonelysheep
Date : March 29 2020, 07:55 AM
it fixes the issue You've chosen a poor algorithm. It's not that it's recursive, just horribly inefficient. Here's a more efficient recursive approach: code :
def climbStairs(self, n, res=1, nxt=1):
if n == 0:
return res
return self.climbStairs(n  1, nxt, res + nxt)
def climbStairs(self, n): # doesn't use 'self', could be class method
if 0 <= n <= 1:
return 1
a = b = 1
for _ in range(n  1):
a, b = b, a + b
return b

divide two integers [leetcode] shift error while using unsigned short
By : user2635606
Date : March 29 2020, 07:55 AM
this one helps. as KamilCuk mentioned, I don't know why he deleted the comment. left shift signed int is undefined behavior. and shifting unsigned short more that 16 is also undefined, as unsigned short is 16 bits. So I have to dealing these edges.

Recursion implementation of LeetCode Problem
By : user3093475
Date : January 02 2021, 04:59 AM
around this issue Here's one answer accepted by LeetCode. I hope the simple logic makes sense: JavaScript code: code :
function f(A, i=2, total=0, prevSeqTotal=0){
if (i >= A.length)
return total
// The number of sequences ending here is 1 (length 3)
// plus the number ending at the previous
// element since those all just got extended.
if (A[i]  A[i1] == A[i1]  A[i2])
return f(A, i + 1, total + 1 + prevSeqTotal, 1 + prevSeqTotal)
return f(A, i + 1, total, 0)
}
console.log(f([3, 1, 1, 3]))

Why is FloodFill algorithm exceeding Leetcode's maximum recursion limit?
By : gip
Date : March 29 2020, 07:55 AM
Hope this helps I believe the code is fine for the case where newColor != og. But my guess is that you are seeing your error because in the case of newColor == og, the stopping condition code :
if grid[sr][sc]!= og:
return

From LeetCode Given an array of integers, return indices of the two numbers such that they add up to a specific target
By : Brandon
Date : March 29 2020, 07:55 AM
hop of those help? This is an exercise on LeetCode. I get an except of , I believe this would work:

