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How to compare integer literals?


How to compare integer literals?

By : user3099621
Date : January 11 2021, 03:34 PM
hop of those help? Use same units for comparison
You probably want to use the same units when you compare $newSize.Size and $threshold. If $threshold is in GB and you want to convert to Bytes for example, you can do this: ($threshold * 1GB)
code :


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How to compare literals in COUNTIF

How to compare literals in COUNTIF


By : user1726724
Date : March 29 2020, 07:55 AM
this will help Named lists in an excel sheet are referenced from another sheet on the same book.
code :
COUNTIF(Range, "=> 5")
C++ compare two string literals

C++ compare two string literals


By : Akash Tyagi
Date : March 29 2020, 07:55 AM
To fix this issue When comparing a string literal with another string literal with the == operator (or !=), is the result well defined? ,
code :
"a" == "a"
"a" != "b"
Integer literals

Integer literals


By : Ujjwal Bhaumik
Date : March 29 2020, 07:55 AM
I wish this help you You cannot assign a value of a type with higher capacity to a type of lower capacity without casting. long can store larger numbers, so it can't be assigned to int.
I am trying to compare string literals and I want to remove repeated literals I want to do it without using POINTERS.,

I am trying to compare string literals and I want to remove repeated literals I want to do it without using POINTERS.,


By : Shruti Chandak
Date : March 29 2020, 07:55 AM
wish helps you I am trying to compare string literals and I want to remove repeated literals I want to do it without using POINTERS. , Correcting your code:
code :
#include <stdio.h>
#include <string.h>

int main()
{
    char str[30];

    printf("Enter strings : ");

    fgets(str,30,stdin);

    char tem[30];

    size_t count;
    size_t county=0;;

    for(count = 0 ; count < strlen(str)-1 ; count++) {
            if(str[count] != str[count+1]) {
                   tem[county++] = str[count];
            }
    }

    tem[county] = '\0';

    printf("%s\n", tem);

    return 0;
}
#include <stdio.h>
#include <string.h>
#include <stdbool.h>

int main()
{
    char str[30];

    printf("Enter strings : ");

    fgets(str,30,stdin);

    char tem[30];

    size_t count;
    size_t county;
    size_t tem_index = 0;
    size_t size_of_string = strlen(str);
    bool found;

    for(count = 0 ; count < size_of_string-1; count++)
    {
        found = false;
        county = count+1;

        while ((found == false) && (county<size_of_string))
        {
            if(str[count] == str[county])
            {
                found = true;
            }
            county++;
        }

        if (found == false)
        {
            tem[tem_index++] = str[count];
        }
    }

    tem[tem_index] = '\0';

    printf("%s\n", tem);

    return 0;
}
#include <stdio.h>
#include <string.h>
#include <stdbool.h>

int main()
{
    char str[30];

    printf("Enter strings : ");

    fgets(str,30,stdin);

    char tem[30];

    size_t count;
    size_t county;
    size_t tem_index = 0;
    size_t size_of_string = strlen(str);
    bool found;

    for(count = 0 ; count < size_of_string-1; count++)
    {
        found = false;
        county = 0;

        while ((found == false) && (county<tem_index))
        {
            if(str[count] == tem[county])
            {
                found = true;
            }
            county++;
        }

        if (found == false)
        {
            tem[tem_index++] = str[count];
        }
    }

    tem[tem_index] = '\0';

    printf("%s\n", tem);

    return 0;
}
Why do user-defined string literals and integer literals have different behavior?

Why do user-defined string literals and integer literals have different behavior?


By : Sereen Vinola
Date : March 29 2020, 07:55 AM
Hope that helps That's how floating point literals work!!
Add a pair of parentheses and it should work:
code :
std::cout << (4_s).count();
std::cout << 4_s .count();
//              ^ Space here!
long double operator""_E(long double);
long double operator""_a(long double);
int operator""_p(unsigned long long);

auto x = 1.0_E+2.0;  // error
auto y = 1.0_a+2.0;  // OK
auto z = 1.0_E +2.0; // OK
auto w = 1_p+2;      // error
auto u = 1_p +2;     // OK
test.cpp:19:10: error: unable to find numeric literal
operator 'operator""_E+2.0'
                    ^^^^^^
 auto x = 1.0_E+2.0;  // error
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