How to fix "Object is possibly undefined"?

How to fix "Object is possibly undefined"?

By : user3045822
Date : December 02 2020, 10:46 PM
I wish did fix the issue. You can leave out the if clause if (countries) { ..., it is not necessary.
It is the next expression which can be undefined:
code :
countries.find((country: Country) => country.id === parseInt(countryId))

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How to suppress "error TS2533: Object is possibly 'null' or 'undefined'"?

How to suppress "error TS2533: Object is possibly 'null' or 'undefined'"?

By : Nakoruru
Date : March 29 2020, 07:55 AM
I hope this helps you . This feature is called "strict null checks", to turn it off ensure that the --strictNullChecks compiler flag is not set.
However, the existence of null has been described as The Billion Dollar Mistake, so it is exciting to see languages such as TypeScript introducing a fix. I'd strongly recommend keeping it turned on.
code :
interface SelectProtected {
    readonly wrapperElement: HTMLDivElement;
    readonly inputElement: HTMLInputElement;

const selectProtected: SelectProtected = {
    wrapperElement: document.createElement("div"),
    inputElement: document.createElement("input")
Typescript "error TS2532: Object is possibly 'undefined'" even after undefined check

Typescript "error TS2532: Object is possibly 'undefined'" even after undefined check

By : rld1111
Date : March 29 2020, 07:55 AM
will help you Because the second access to input.query happens inside another function the arrow function passed in to forEach. Flow analysis does not cross function boundaries, so since you are in another function you need to test again.
An alternative to the double test would be to use a local variable, since the type of the variable is locked in on assignment and it will not include the undefined type :
code :
function testStrict(input: { query?: { [prop: string]: string } }) {
    if (input.query) {
        const query = input.query;
        Object.keys(input.query).forEach(key => {
    return input;
Firestore cloud functions Comment Counter: How to fix "Object is possibly undefined"?

Firestore cloud functions Comment Counter: How to fix "Object is possibly undefined"?

By : David Flores
Date : March 29 2020, 07:55 AM
this one helps. The error is telling you that the error is on line 38. Since you didn't say which line that is, I'm going to guess that it's on this one:
code :
    const data = snapshot.data()
const data = snapshot.data()
if (data) {
    return admin.firestore().doc('posts/{postID}').update({postCommentsTot: data.postCommentsTot + 1});
else {
    return null
Cloud Functions-TypeScript- "Object is possibly 'undefined'.ts(2532)"

Cloud Functions-TypeScript- "Object is possibly 'undefined'.ts(2532)"

By : jofox
Date : March 29 2020, 07:55 AM
will help you Your TypeScript configuration almost certainly has strict type checking enabled, which will give you this warning when you try to access properties of something that could be null or undefined. Check your tsconfig.json and look for "strict": true" in the compiler options. The TypeScript bindings for the DataSnapshot.data() API says that the return value of data() could anything (including null or undefined), and TypeScript is forcing you to deal with this fact correctly at compile time so that your code doesn't crash at runtime.
The sample code you're looking at is plain JavaScript, which does not have any type checking. It is assuming that the snapshot will not be null or undefined. If you found this to be confusing or problematic, please use the "send feedback" link at the top of the page of documentation to explain what was confusing to you.
Getting "Object possibly undefined" when triggering Cloud Function on document creation

Getting "Object possibly undefined" when triggering Cloud Function on document creation

By : martyzzs
Date : March 29 2020, 07:55 AM
I wish this helpful for you My first guess is that the typescript compiler can't know whether snap.data() has a value, so you'll need to check for that:
code :
  const newValue = snap.data();

  if (newValue) {
    const email = newValue.email;
    const phone = newValue.phone;

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