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Make a checkbox checked if its id is present in an array


Make a checkbox checked if its id is present in an array

By : user3045542
Date : December 02 2020, 10:46 PM
fixed the issue. Will look into that further Try this solution
{{element.id}}
code :


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How would you make a checkbox in a Outline View become checked when all it's children's checkbox's are checked?

How would you make a checkbox in a Outline View become checked when all it's children's checkbox's are checked?


By : SpawN
Date : March 29 2020, 07:55 AM
wish helps you Whenever you check a box, check to see if all its siblings are checked. If so, check the parent. (And run the check again on that level.)
To do that... well, your NSOutlineView has a data source, right? Something that's telling it what to display? Well, in the method called by the checkbox when it's clicked (whatever you set that up to be), get the parent object behind the row which was clicked, and then update its status. If you don't have a direct reference to the checkbox from the model, you can use -[NSOutlineView parentForItem:] to find it.
Make dynamic checkbox auto checked if match from another array

Make dynamic checkbox auto checked if match from another array


By : user3775381
Date : March 29 2020, 07:55 AM
This might help you Let's say your array of autochecked fruit is $autocheck_array. Then you can use:
code :
<?php echo '<input type="checkbox" id="fruit_id[]" name="fruit_id[]" value="' 
. $fruit_id . '"' . (in_array($fruit_name, $autocheck_array) ? ' checked="checked"' : '') 
. '"/>' . $fruit_name . "\n"; ?>
Make checkbox array stay checked after submitting the form

Make checkbox array stay checked after submitting the form


By : Santosh Pandit
Date : March 29 2020, 07:55 AM
will be helpful for those in need All working here... Any issues then please ask. I will fix them.
This code displays two menus from entries stored in two tables. It allows the user to select the entries that they wish and persists the 'checked' items by setting the 'checked' attribute on the output screen by checking the $_POST array.
code :
<?php
    /* debug */ var_dump($_POST);

    $mysqli = new mysqli('localhost', 'test', 'test', 'testmysql');

    $query  = '';
    $query .= "SELECT id, ediens FROM menu_edieni_otrie order by id;";

    $query .= "SELECT id, ediens FROM menu_edieni_zupas order by id;";

    echo "<body>\n";
    echo "<form name='otrie_edieni' action='' method='post'>\n";
    echo "<table border='1px'>\n";
    echo "<tr>\n";
    echo "<td>\n";
    /* execute multi query */
    if ($mysqli->multi_query($query)) {
        if ($result = $mysqli->store_result()) {

            while ($row = $result->fetch_array()) {
                echo "<input type='checkbox' name='ediens2[]' value='";
                printf ("%s", $row['id']);
                echo "' ";
                echo isset($_POST['ediens2']) && in_array($row['id'], $_POST['ediens2']) ? ' checked="checked"' : '';
                echo "/>";
                printf ("%s </br>\n ", $row[1]);
            }
            $result->free();
        }
    }

    echo "</td>\n";
    echo "<td>\n";
    // try and get the next results (zupas)

    if ($mysqli->more_results()) {          // any results from the zupas menu?
        $mysqli->next_result();             // get them...
        $result = $mysqli->store_result();  // access them...

        while ($row = $result->fetch_array()) { // process them
            echo "<input type='checkbox' name='zupas2[]' value='";
            printf ("%s", $row['id']);
            echo "' ";
            // we need to set the 'checked' attribute if the user ticked the box.
            // we check the $_POST array to see if the current value is in there ans set it checked if it is.
            echo isset($_POST['zupas2']) && in_array($row['id'], $_POST['zupas2']) ? ' checked="checked"' : '';
            echo "'/>";
            printf ("%s </br>\n ", $row[1]);
        }
        $result->free();
    }
    echo "</td>\n";
    echo "</tr>\n";
    echo "</table>";
    echo "<input type='submit' name='formSubmit' value='Submit' />";
    echo "</form>\n";
    echo "</body>";
?>
How to retrieve data from MySQL array and make checkbox checked in list

How to retrieve data from MySQL array and make checkbox checked in list


By : xyxxyxxy
Date : March 29 2020, 07:55 AM
hop of those help? When you fetch the current user's select_fi previously checked boxes (e.g. 1,2,3 ) you can convert it to PHP array with $current_user_checked_boxes_ids = explode(",",$string).
And then, inside the PHP loop you have to print the checkboxes in HTMLyou can write something like:
code :
if (in_array(
$current_check_box_id, 
$current_user_checkboxes_ids))
echo '<input type="checkbox" checked="checked">';
else
echo '<input type="checkbox">';
How to make an array of items which are checked in checkbox

How to make an array of items which are checked in checkbox


By : Chris Lloyd
Date : March 29 2020, 07:55 AM
This might help you For a plain javascript solution, you can use document.querySelectorAll().
Retrieve the checkboxes and then loop over them, then push() all of the ones that have the checked: true property to an array called checked.
code :
var checkboxes = document.querySelectorAll("input[type=checkbox]");
var submit = document.getElementById("submit");

function getChecked() {
  var checked = [];

  for (var i = 0; i < checkboxes.length; i++) {
    var checkbox = checkboxes[i];
    if (checkbox.checked) checked.push(checkbox.value);
  }

  return checked;
}

submit.addEventListener("click", function() {
  var checked = getChecked();
  console.log(checked);
});
<input type="checkbox" value="first" checked>
<input type="checkbox" value="second" checked>
<input type="checkbox" value="third" checked>

<input type="submit" id="submit">
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