How to process negative shifts in Caesars Cipher (Javascript)

How to process negative shifts in Caesars Cipher (Javascript)

By : user3045077
Date : December 01 2020, 04:52 PM
seems to work fine Your code only works for positive caesar shifts, because in
String.fromCharCode(((prePoint - 65 + shift) % 26) + 65);
code :
let newPoint = (prePoint - 65 + shift) % 26;
if(newPoint < 0) newPoint += 26;
return String.fromCharCode(newPoint + 65);
if(shift < 0) { shift = 26 + (shift % 26);}
function caesar(message, shift) {
  if (shift < 0) {
    shift = 26 + (shift % 26);
  return message
    .split("") //splits it into an array
    .map(message => { //does the following to each element in the array
      normalStr = String.fromCharCode(message.charCodeAt())
      prePoint = message.charCodeAt() //gets the charcode of element  
      //if/else checks to see if upper or lower case
      if (prePoint >= 65 && prePoint <= 90) { //upper case
        return String.fromCharCode(((prePoint - 65 + shift) % 26) + 65);
      } else if (prePoint >= 97 && prePoint <= 122) { //lower case
        return String.fromCharCode(((prePoint - 97 + shift) % 26) + 97)
      } else {
        return normalStr;

console.log(caesar('Mjqqt, Btwqi!', -5)); // Hello World!

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EDX set 5 - caesars cipher

EDX set 5 - caesars cipher

By : zegufe
Date : March 29 2020, 07:55 AM
To fix the issue you can do Your first problem is that applyCoder can't work as written.
buildCoder builds a dict that only has entries for letters. But applyCoder tries to look up anything that's not in string.punctuation, or == ' ', or in str(range(10)). I think you wanted string.digits there (because str(range(10)) is '[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]'), but it's still going to blow up if you give it, say, a newline, which a file called story.txt is almost guaranteed to have.
code :
for l in text:
    new_text += coder.get(l, l)
if currentMatch>wordsFound:
$ ln -s /usr/share/dict/words words.txt
$ echo -e "This is a test.\n\nIs it good enough? Let's see.\n" | rot13 > story.txt
$ python caesar.py
Loading word list from file...
   235886 words loaded.
Loading word list from file...
   235886 words loaded.
Loading word list from file...
   235886 words loaded.
This is a test. 

Here's some text. Is it enough? Let's see.
if currentMatch>wordsFound:
    print i, currentMatch, wordsFound
Java caesars cipher brute forcing

Java caesars cipher brute forcing

By : Nguyễn Xuân Dũng
Date : March 29 2020, 07:55 AM
this will help You need to convert the alphabet array to List to use the indexOf method:
code :
private List<Character> alphabetList = java.util.Arrays.asList(alphabet);
decodedText[i] = alphabet[(alphabetList.indexOf(message[i])+key) % alphabet.length];
public class Test01 {

    private Character[] alphabet = {'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'};
    private char[] decodedText;
    private String[] plainText;
    private java.util.List<Character> alphabetList;

    public Test01(){
        alphabetList = java.util.Arrays.asList(alphabet);
        plainText = new String[alphabet.length];

    public String[] producePlaintext(String cipherText) {
        //put each letter of the ciphertext in an array of characters in the upper case format
        char[] message = cipherText.toUpperCase().toCharArray();
        //loop through all the possible keys
        for (int key = 0; key < alphabet.length; key++) {
            //set the value of the decrypted array of characters to be the same as the length of the cipher text
            decodedText = new char[message.length];
            //loop through the characters of the ciphertext
            for (int i = 0; i < message.length; i++) {

                //if character is not space
                if (message[i] != ' ') {
                    //shift the letters
                    decodedText[i] = alphabet[(alphabetList.indexOf(message[i])+key) % alphabet.length];
                    decodedText[i] = ' ';
            plainText[key] = String.valueOf(decodedText);
        return plainText;

    public static void main(String[] args) {
        Test01 t = new Test01();
        for(String pt : t.producePlaintext("abc")) {

Javascript Caesars Cipher algorithm code break down needed?

Javascript Caesars Cipher algorithm code break down needed?

By : Jeremy White
Date : March 29 2020, 07:55 AM
it should still fix some issue L => declares an arrow function, which is a shorthand syntax for:
code :
function(L) {
    return String.fromCharCode((L.charCodeAt(0) % 26) + 65));
function rot13(str) { // LBH QVQ VG!
  return str.replace(/[A-Z]/g, L => String.fromCharCode((L.charCodeAt(0) % 26) + 65));

// Change the inputs below to test
console.log(rot13("ABMNTZ !"));
Caesars Cipher in JavaScript - Why does 'A' turn into '[' here?

Caesars Cipher in JavaScript - Why does 'A' turn into '[' here?

By : Abhijit Jamble
Date : March 29 2020, 07:55 AM
should help you out It's a simple fix, changing > to >= Don't forget that arrays are zero-indexed. if((alphabet.indexOf(String.fromCharCode(charCodes[i])) + 13) >= alphabet.length)
Caesars cipher - Conditional jump or move depends on uninitialised value

Caesars cipher - Conditional jump or move depends on uninitialised value

By : Hey Romey
Date : September 27 2020, 08:00 AM
this will help Shift does not terminate dst (decoded), which could cause strlen to go into other memory. Decoded isn't large enough to contain the string terminator.
As a style note:
code :
for (int i = 0; i < strlen(src); i++)
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