How to convert void (__thiscall MyClass::* )(void *) to void (__cdecl *)(void *) pointer
By : user2844509
Date : March 29 2020, 07:55 AM
help you fix your problem You can't. You should use a static function instead (not a static member function, but a free function). code :
// IThread.h
class IThread
{
public:
void BeginThread();
virtual void ThreadMain() = 0;
};
// IThread.cpp
extern "C"
{
static void __cdecl IThreadBeginThreadHelper(void* userdata)
{
IThread* ithread = reinterpret_cast< IThread* >(userdata);
ithread->ThreadMain();
}
}
void IThread::BeginThread()
{
m_ThreadHandle = _beginthread(
&IThreadBeginThreadHelper,
m_StackSize, reinterpret_cast< void* >(this));
}
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Void System.Threading.Monitor.Enter Error when using ILMerge
By : Anna Lerner
Date : March 29 2020, 07:55 AM
I wish did fix the issue. What version of the framework are you using? There is a targetplatform option you may need to set if you are using 4.0/4.5 for example. /targetplatform:version,platformdirectory
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error: argument of type ‘void* (Thread::)(void*)’ does not match ‘void* (*)(void*)’
By : ADI POLAK
Date : March 29 2020, 07:55 AM
it fixes the issue pthread_create is a C function, and knows nothing of C++ member functions. You'll need to give it a static or non-member function, and pass a pointer to your Thread object via the final argument of pthread_create; something like: code :
class Thread
{
virtual void* run(void *params) = 0;
void start(void * params)
{
this->params = params;
pthread_create(&threadId, 0, &Thread::static_run, this);
}
static void * static_run(void * void_this)
{
Thread * thread_this = static_cast<Thread*>(void_this);
return thread_this->run(thread_this->params);
}
private:
pthread_t threadId;
void *params;
};
std::thread thread;
void start(void * params)
{
thread = std::thread([this]{run(params);});
}
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.NET Interop 'Method not found: 'Void System.Threading.Monitor.Enter..
By : Connor Hagan
Date : March 29 2020, 07:55 AM
should help you out When compiling the C# dll, it is targeting a .NET version prior to framework 4. Make sure the setting in the compiler is targeting the correct platform version.
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how does jvm enter in public static void main?
By : Sachin Hatvalne
Date : March 29 2020, 07:55 AM
will be helpful for those in need It is not JVM itself who invokes main method. This is rather a job of Java launcher, i.e. java.exe. Java launcher is a small program written in C that uses regular JNI functions:
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