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How to separate the prefix in words that are 'di'?


How to separate the prefix in words that are 'di'?

By : likhin
Date : November 28 2020, 12:01 PM
will help you I want to separate some prefixes that are integrated into words after the word "di" is followed by letters. , This expression might work to some extent:
code :
(di)(\S+)
import re    
regex = r"(di)(\S+)"    
test_str = "dipermudah diperlancar"    
subst = "\\1 \\2"    

print(re.sub(regex, subst, test_str))


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Search and replace multiple words with notepad++ (the text uses pipe to separate words)

Search and replace multiple words with notepad++ (the text uses pipe to separate words)


By : pismo
Date : March 29 2020, 07:55 AM
To fix the issue you can do | is a regex special char, you have to escape it using \|.
In your case, replacing \|C485\|01\|(.*\|0,0000\|) by |C481|04|$1 should suit your needs.
Javascript: Find exactly 10 words in a prefix tree that start with a given prefix

Javascript: Find exactly 10 words in a prefix tree that start with a given prefix


By : Ramon Thurler Palomo
Date : March 29 2020, 07:55 AM
Any of those help Basically I take your model and apply a new method getWords(word[, count]) to the Trie class. I changed the method contains because I need the functionality in getWords as well. So I created a new method getNode, which returns the node where the word or part is found.
The method getWords first looks up the word (part) and then iterates through the data structure. When a word is found it is pushed to the result set. If the result set length is greater or equal to the required length, then the iteration (hence Array.prototype.some) is terminated and the recursive call of fork is stopped.
code :
    that.getWords = function (word, count) {

        function fork(n, w) {

            function child(c) {
                return fork(n.children[c], w + c);
            }

            n.isWord && words.push(w);
            return words.length >= count || Object.keys(n.children).some(child);
        }

        var words = [],
            current_node = that.getNode(word);

        if (current_node) {
            fork(current_node, word);
            return words;
        }
    }
var Trie = function () {

    var that = Object.create(Trie.prototype);
    that.children = {}; //mapping: next character -> child nodes
    that.isWord = false;

    that.insertWord = function (word) {
        var current_node = that;
        for (var i = 0; i < word.length; i++) {
            var c = word[i]
            //if character is not in the trie already, add it
            if (!(c in current_node.children)) {
                current_node.children[c] = Trie();
            }
            //update current_node
            current_node = current_node.children[c];
        };

        //after adding all the chars of the word,
        //you are at the end of a word
        current_node.isWord = true;
    }

    that.insertWords = function (words) {
        for (var i = 0; i < words.length; i++) {
            that.insertWord(words[i]);
        }
    }

    that.getNode = function (word) {
        //start at the root
        var current_node = that;
        for (var i = 0; i < word.length; i++) {
            var c = word[i];

            //if the word's character isn't a child of the current_node,
            //the word isn't in the trie
            if (!(c in current_node.children)) {
                return;
            }
            //move down the trie, update current_node
            current_node = current_node.children[c];
        };
        return current_node;
    }

    that.contains = function (word) {
        var current_node = that.getNode(word);
        if (current_node) {
            return current_node.isWord;
        }
        return false;
    }

    that.getWords = function (word, count) {

        function fork(n, w) {

            function child(c) {
                return fork(n.children[c], w + c);
            }

            n.isWord && words.push(w);
            return words.length >= count || Object.keys(n.children).some(child);
        }

        var words = [],
            current_node = that.getNode(word);

        if (current_node) {
            fork(current_node, word);
            return words;
        }
    }

    // freeze does lock the isWord property, which is not required here
    //Object.freeze(that);
    return that;
}

var trie = new Trie();
trie.insertWords([
    'car', 'cool', 'i', 'in', 'indeed', 'independence', 'india', 'indoor', 'induction',
    'industrial', 'industry', 'indwell', 'inferior', 'informal', 'inhale', 'inn',
    'inside', 'instance', 'intrepid', 'of', 'off', 'other', 'tea', 'ted', 'ten',
    'to', 'zoo', 'zoom'
]);
document.write(trie.contains('motor') + '<br>'); // false
document.write(trie.contains('te') + '<br>'); // false
document.write(trie.contains('ten') + '<br>'); // true
document.write('<pre>' + JSON.stringify(trie.getWords('ind'), 0, 4) + '</pre>');
document.write('<pre>' + JSON.stringify(trie.getWords('in', 10), 0, 4) + '</pre>');
document.write('<pre>' + JSON.stringify(trie, 0, 4) + '</pre>');
Rails split sentence into separate words but substitute certain words

Rails split sentence into separate words but substitute certain words


By : j.woon
Date : March 29 2020, 07:55 AM
seems to work fine What the goal is , You could do something like this:
code :
sentence = 'I helped Adidas brand rebuild their design system'
words  = ["Adidas", "brand"]

sentence = sentence.split(/\W+/)
sentence.map! do |word|
  words.include?(word) ? "<span class='highlight'>#{word}</span>" : "<span>#{word}</span>"
end


puts sentence 
# => 
<span>I</span>
<span>helped</span>
<span class='highlight'>Adidas</span>
<span class='highlight'>brand</span>
<span>rebuild</span>
<span>their</span>
<span>design</span>
<span>system</span>
How convert string of separate words to separate elements of list by using stream api

How convert string of separate words to separate elements of list by using stream api


By : user1486520
Date : March 29 2020, 07:55 AM
Does that help Try to studying Stream API. So, I have a list of strings like this: , You may do
code :
List<String> initial;
List<String> all = initial.stream().flatMap(str -> Arrays.stream(str.split("\\.")))
                                   .collect(Collectors.toList());
I have made a program in C++ to separate words from a line by spacebar and display those words as an array. What's wrong

I have made a program in C++ to separate words from a line by spacebar and display those words as an array. What's wrong


By : Veranbandi
Date : October 07 2020, 07:00 PM
I hope this helps . I suggest you use a string, as you already included it. And 'List is not really necessary in this situation. Try making a single for loop where you separate your line into words, in my opinion when you work with arrays you should use for loops. In your for loop, as you go through the line, you could just add a if statement which determines whether you're at the end of a word or not. I think the problem in your code is the multiple loops but I am not sure of it.
I provide you a code which works. Just adapt it to your display requirements and you will be fine
code :
#include <iostream>
#include <string>
using namespace std;

int main()
{
    string line = "Hi there buddy";

    for (int i = 0; i < line.size(); i++) {
        if (line[i] == ' ') {
            line[i + 1] = toupper(line[i+1]);
            cout<<'\n';
        } else {
            cout<<line[i];
        }

    }

    return 0;
} ```
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