Trying to split byte in a byte array into two nibbles

Trying to split byte in a byte array into two nibbles

By : user3042422
Date : November 28 2020, 12:01 PM
I think the issue was by ths following , Use pkt[0] to get the first byte as an int 69. Then, you can use bit-wise shift (<<, >>) and bit-wise and (&) operators against the int object, to split into nibbles:
code :
>>> pkt = bytearray(b'EAB82348...')
>>> b = pkt[0]  # 69 == 0x45
>>> (b >> 4) & 0xf  # 0x45 -> 0x4 -> 0x4
>>> (b) & 0xf  # 0x45 -> 0x5

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c# left-shift nibbles in a byte array

c# left-shift nibbles in a byte array

By : Sabir Mohamed
Date : March 29 2020, 07:55 AM
this one helps. Not sure if this is homework or not, but the shift left and combine part will look something like this:
code :
var pos = 0;
var newByte = b1[pos] << 4;
newByte |= b2[pos]
What is the meaning of clojure output in repl when evaluating this line: (class (byte-array [(byte 0) (byte 1) (byte 2)]

What is the meaning of clojure output in repl when evaluating this line: (class (byte-array [(byte 0) (byte 1) (byte 2)]

By : Hiten Damania
Date : March 29 2020, 07:55 AM
I hope this helps you . The JVM uses [ to indicate an array, and what follows is the class of the component type. For the primitive type byte, that is represented as the single letter B. See Retrieving array class name for one discussion (of many) on this topic.
C# Find offset of byte pattern, check specific byte, change byte, export part of byte array

C# Find offset of byte pattern, check specific byte, change byte, export part of byte array

By : Malavos
Date : March 29 2020, 07:55 AM
I wish this help you This could be long one. I do have a binary file, that contains some information. , how do I do bytes(offset=IndexCamera+2) == 0x08 ?
code :
if(bytes[IndexCamera+2] == 0x08)....
Python split byte into high & low nibbles

Python split byte into high & low nibbles

By : tikusgot
Date : March 29 2020, 07:55 AM
wish help you to fix your issue If you wanted to get the high and low nibble of a byte. In other words split the 8-bits into 4-bits.
Considering the data string is a string of bytes as hexadecimals, then you could simply do:
How to build byte array from bytes and nibbles in C#

How to build byte array from bytes and nibbles in C#

By : Tonyc
Date : March 29 2020, 07:55 AM
I wish this help you If all items are supposed to be hexadecimal, Linq and Convert are enough:
code :
string[] content = {"0x1", "5", "0x8", "7", "0x66"};

byte[] result = content
  .Select(item => Convert.ToByte(item, 16))
byte[] result = content
  .Select(item => Convert.ToByte(item, item.StartsWith("0x", StringComparison.OrdinalIgnoreCase) 
    ? 16
    : 10))
private static byte[] Nibbles(IEnumerable<string> data) {
  List<byte> list = new List<byte>();

  bool head = true;

  foreach (var item in data) {
    byte value = item.StartsWith("0x", StringComparison.OrdinalIgnoreCase) 
      ? Convert.ToByte(item, 16)
      : Convert.ToByte(item, 10);

    // Do we have a nibble? 
    // 0xDigit (Length = 3) or Digit (Length = 1) are supposed to be nibble
    if (item.Length == 3 || item.Length == 1) { // Nibble
      if (head)                                 // Head
        list.Add(Convert.ToByte(item, 16));
      else                                      // Tail
        list[list.Count - 1] = (byte)(list[list.Count - 1] * 16 + value);

      head = !head;
    else { // Entire byte
      head = true;


  return list.ToArray();


string[] content = { "0x1", "5", "0x8", "7", "0x66" };

Console.Write(string.Join(", ", Nibbles(content)
  .Select(item => $"0x{item:x2}").ToArray()));
// "0x1", "5" are combined into 0x15
// "0x8", "7" are combined into 0x87
// "0x66"  is treated as a byte 0x66
0x15, 0x87, 0x66
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