Instantiating a python class from a module by full name

» chash » Instantiating a python class from a module by full name

By : user3042302

Date : November 27 2020, 05:23 PM

around this issue I've managed to write an extension class which would provide a similar functionality to a regular python's "from X import Y". In the end I had to use the default ImportModule to import the very root of the module hierarchy and traverse down the structure to find the necessary module:

code :

private static PythonModule TraverseDown(PythonModule module, string moduleName)
{
    return (PythonModule) module.Get__dict__()[moduleName];
}

private static PythonModule TraverseToTarget(ScriptScope scope, string moduleName)
{
    // The root of the module was already imported by the engine's import module call. 
    var moduleNameParts = moduleName.Split('.').Skip(count: 1).ToList();
    var rootModule = scope.GetVariable<PythonModule>(moduleNameParts.First());
    return moduleNameParts.Skip(count: 1).Aggregate(rootModule, TraverseDown);
}

public static dynamic ImportFromModule(this ScriptEngine engine, string moduleName, string targetImport)
{
    var rootModuleScope = engine.ImportModule(moduleName);
    var targetModule = TraverseToTarget(rootModuleScope, moduleName);
    return targetModule.Get__dict__()[targetImport];
}

// Here's a sample input:
var moduleName = "sp.content.abilities.torpedo"
var className = "AbilityTorpedo"

// Here's my module loading and class instaitiation
var moduleScope = ScriptEngine.ImportFromModule(moduleName, className);
return ScriptEngine.Operations.CreateInstance(scriptClass);

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Instantiating a ruby class that is in a Module from within C#

By : Sean.SanzoMaldini

Date : March 29 2020, 07:55 AM

With these it helps I know this is kind of a hack/workaround, but I managed to do it this way:
Add the next code to the end of your ruby file:

code :

def hack(s)
  eval(s)
end

var engine = Ruby.CreateEngine();

var scope = engine.ExecuteFile(@"c:\code\generator\lib\generator\generator_cmd_line.rb");

var genCmdLineObj = engine.Execute(String.Format("hack('{0}::{1}')", "Generator", "CmdLine"), scope);
var cmdLineObj = engine.Operations.CreateInstance(genCmdLineObj);
var results = engine.Operations.InvokeMember(cmdLineObj, "run");
return Content(results);

How can I get a full list of class members without instantiating a class?

By : user3432772

Date : March 29 2020, 07:55 AM

Any of those help Good day! , I'm not sure I know what you mean:

code :

class a(object):
    b = 'a'
    c = 'd'

print dir(a)

['__class__', '__delattr__', '__dict__', '__doc__', '__format__', '__getattribute__', '__hash__', '__init__', '__module__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'b', 'c']

print [i for i in dir(a) if not i.endswith('__')]

Dynamically importing a module and instantiating a class in Python

By : user3453363

Date : March 29 2020, 07:55 AM

This might help you If everything in your module are classes that you should instanciate, try something like this :
for a in actions:

code :

try:
    module = __import__("actions.%s" % a, globals(), locals(), fromlist=["*"])
    # What goes here?
    # let's try to grab and instanciate objects
    for item_name in dir(module):
        try:
           new_action = getattr(module, item_name)()
           # here we have a new_action that is the instanciated class, do what you want with ;)
        except:
           pass

except ImportError:
    pass

VBA - Naming and Instantiating a Class Module

By : Olusegun J

Date : March 29 2020, 07:55 AM

it should still fix some issue VBA is not case sensitive like C# so class1 and Class1 are the same things..
There is nothing seriously wrong (meaning: since the compiler allows that...) with using the same name for an object instance as its class except in general it would be considered a really bad programming practice to use the same name for class instance as its class.