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In Ruby, why doesn't ternary operator work when using a puts function inside an each statement?


In Ruby, why doesn't ternary operator work when using a puts function inside an each statement?

By : user3041561
Date : November 26 2020, 03:04 PM
Hope that helps This is caused by ambiguous arguments. Ruby, unlike many other languages such as JavaScript, is really lax about requiring brackets puts x and puts(x) are equivalent. Where this breaks down is when it's not clear which are arguments, and which are part of other syntax.
For example, if f is a method that takes 1-3 arguments and x and y are variables, then what is the meaning of:
code :
f x, f x, y
array = [1,2,3]
array.each { |x| puts x > 2 ? "lower" : "higher"}


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PHP - class property with ternary operator confsuion - could someone explain why this doesnt work

PHP - class property with ternary operator confsuion - could someone explain why this doesnt work


By : SM06
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Use the __construct function. This will set var when the class is loaded:
code :
class Base_Class {
        public $var;
        function __construct(){
            $this->var = (substr($_SERVER['HTTP_HOST'], -3) == 'dev') ? TRUE : FALSE;
        }
}
using ruby ternary operator to puts a value and increment a variable

using ruby ternary operator to puts a value and increment a variable


By : lordpentax
Date : March 29 2020, 07:55 AM
wish of those help I'd like to puts a 1 if a test is true and a puts a 0 if it is not. I'd also like to increment a counter that counts each time a test is successful. I have this right now: , Well, I think the code you're trying to write is
code :
puts test1 ? (sum += 1; 1) : 0
puts test2 ? (sum += 1; 1) : 0
puts test3 ? (sum += 1; 1) : 0
puts test4 ? (sum += 1; 1) : 0
Function which puts strings out of vars together and puts them into an input doesnt work

Function which puts strings out of vars together and puts them into an input doesnt work


By : Abdelwahid Muller
Date : March 29 2020, 07:55 AM
should help you out By looking at your code I added var randfloat5 = ""; after line 25. I think it solved your problem and the code worked.
Ternary operator Ruby puts

Ternary operator Ruby puts


By : Samson Daniel
Date : March 29 2020, 07:55 AM
I hope this helps you . The answer to your question is that the ternary operator has higher precedence than the method call, in the same way * has higher precedence than +, so the ternary expression is evaluated before its result is passed to the method.
In other words, this:
Is it possible in C++ to use ternary operator to select a comparison operator inside an if-statement?

Is it possible in C++ to use ternary operator to select a comparison operator inside an if-statement?


By : beqsona13
Date : September 26 2020, 04:00 AM
this will help While refactoring code to minimize the number of lines of code, I wonder if it's possible to combine two similar if-statements with the only difference being the comparison operator, e.g. , You can use std::less and std::greater :
code :
int a = 0, b = 0;
if(c ? std::less<int>{}(a, b) : std::greater<int>{}(a, b))
  a = b;
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