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How to replace a string using the original matched value


How to replace a string using the original matched value

By : JulesA
Date : November 22 2020, 12:01 PM
wish of those help If I understand correctly, you can use substitution:
code :
public static string Highlight(this string source, string highlightString)
{
    var regex = new Regex(highlightString, RegexOptions.IgnoreCase);
    var r = regex.Replace(
            source, 
            "<span class=\"highlight\">$&</span>");
}
<span class="highlight">Trip</span> Nordic


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string manipulation in JavaScript: retrieve the matched text and then replace the matched text

string manipulation in JavaScript: retrieve the matched text and then replace the matched text


By : Ahmed Sid
Date : March 29 2020, 07:55 AM
may help you . JavaScript text manipulation , You can make the second argument to replace a function:
code :
str = "testing one two three";
str = str.replace(/one/g, function(match) {

    return match.toUpperCase();
});
str = "testing one two three";
str = str.replace(/(on)(e)/g, function(match, group0, group1) {

    return match.toUpperCase();
});
Replace part of matched string with Regex.Replace

Replace part of matched string with Regex.Replace


By : Amirhossein
Date : March 29 2020, 07:55 AM
it helps some times Suppose I have string like this ".1.12.3.4.12.4." , Try this:
code :
var input = ".1.12.3.4.12.4.";
var output = Regex.Replace(input, @"\.(\d)(?=\.)", ".0$1");
Console.WriteLine(output); // .01.12.03.04.12.04.
Scala: how to replace strings using the original matched values

Scala: how to replace strings using the original matched values


By : Joseph thompson
Date : March 29 2020, 07:55 AM
hope this fix your issue Using RegularExpressions, you can use $1 to get the result of the first capturing group (in parenthesis):
code :
val regex = "(\\d+)".r
val text = "hello 45 hello 4 bye"
val result = regex.replaceAllIn(text, "$1.0")
// result: String = hello 45.0 hello 4.0 bye
Run sonar on android project: The class 'foo.bar.R$string' could not be matched to its original source file

Run sonar on android project: The class 'foo.bar.R$string' could not be matched to its original source file


By : Saúl Moctezuma
Date : March 29 2020, 07:55 AM
like below fixes the issue When I run sonar analysis of my android project, I always get lots of messages about .class files generated by Android resource compilation like following , Problem is solved with sonar.findbugs.excludesFilters property
code :
sonarqube {
    properties {
        property 'sonar.findbugs.excludesFilters', 'findbugs-filter.xml'
    }
}
<FindBugsFilter>
    <Match>
        <Or>
            <Class name="~.*\.R\$.*"/>
            <Class name="~.*\.Manifest\$.*"/>
        </Or>
    </Match>
</FindBugsFilter>
pycharm regex replace string and keep the original matched ones

pycharm regex replace string and keep the original matched ones


By : user2734751
Date : March 29 2020, 07:55 AM
Any of those help Try using $0 in the replacement, which should correspond to the entire matched line:
code :
Find:    ^and .* >='2019-01-01'$
Replace: -- $0
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