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Repeated replacement of characters in String


Repeated replacement of characters in String

By : Vash
Date : November 22 2020, 12:01 PM
it helps some times You could create a Map which will hold your mapping.
Then just iterate other the original String.
code :
Map<Character, Character> m = new HashMap<>();
m.put('F','0');
....

StringBuilder sb = new StringBuilder();
for(char c : originalString.toCharArray()){
   sb.append(map.get(Character.toUpperCase(c)));
} 
String finalString = sb.toString();


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gsub replacement not working when trying to remove repeated characters

gsub replacement not working when trying to remove repeated characters


By : NameOnDisplay
Date : March 29 2020, 07:55 AM
it helps some times Your code has two problems: (1) you have a stray \\ before the {2,} and (2) [[:alpha:]] will match any sequence of letters, not only a sequence of identical letters. Here is a way of doing what I believe you want, usingthe back-reference \1 to say "more letters like the first one":
code :
gsub('([[:alpha:]])\\1{2,}', '\\1\\1', x)
Count of repeated characters including the non-repeated ones in a string python

Count of repeated characters including the non-repeated ones in a string python


By : Baibhav Verma
Date : March 29 2020, 07:55 AM
wish of those help I am need to find the count of repeated character by groups of letters for e.g if I have a string, s = "hggdsaajhjhajadj", then I need the counts as , The following function does what you specified:
code :
def mycount(s):
        i = 0
        res = []
        while i<len(s):
                j = i+1
                while j<len(s) and s[i] == s[j]:
                        j += 1
                res.append( (s[i],j-i) )
                i = j
        return res
Reducing repeated characters in a string while having a maximum number of repeated characters allowed

Reducing repeated characters in a string while having a maximum number of repeated characters allowed


By : Rachel
Date : March 29 2020, 07:55 AM
may help you . I have no idea how I would even begin to tackle this problem, , Simple solution:
code :
void x(char *s, int n)
{
    char *cp= s;
    int i, j;

    while (*cp) {
        i= 1;
        while (*(cp+i) && ((*(cp+i))&~32)==((*cp)&~32)) i++;    // count character repeat
        for (j=0; j<n && j<i; j++)              // repeat at most max repeat (n)
            *s++ = *(cp+j);
        cp += i;
    }
    *s= '\0';
}
Replace certain characters in an input-string with pre-defined replacement characters (python 3)

Replace certain characters in an input-string with pre-defined replacement characters (python 3)


By : Tim H
Date : March 29 2020, 07:55 AM
I hope this helps . That's easy, just define a dictionary which maps characters to their replacement.
code :
>>> replacers = {'A':'Z', 'T':'U', 'H':'F'}
>>> inp = raw_input()
A T H X
>>> ''.join(replacers.get(c, c) for c in inp)
'Z U F X'
>>> [replacers.get(c, c) for c in inp]
['Z', ' ', 'U', ' ', 'F', ' ', 'X']
>>> 'x'.join(['a', 'b', 'c'])
'axbxc'
print all possible string without adjacent equal characters from repeated characters string

print all possible string without adjacent equal characters from repeated characters string


By : le chen
Date : March 29 2020, 07:55 AM
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