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return value of anonymous function


return value of anonymous function

By : H. Morad
Date : November 22 2020, 11:17 AM
like below fixes the issue as you have mentioned, you have a global object named DOM, using it you can do it like:
code :
matches: (DOM._getMatches = function(){
    return Element.prototype.matchesSelector 
    || Element.prototype.webkitMatchesSelector 
    || Element.prototype.mozMatchesSelector 
    || Element.prototype.msMatchesSelector 
    || Element.prototype.oMatchesSelector 
    || Element.prototype.matches 
    || Element.prototype.webkitMatches
    || Element.prototype.mozMatches
    || Element.prototype.msMatches
    || Element.prototype.oMatches;
})(),
DOM._getMatches()


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JavaScript: When assigning an anonymous function to a variable, function return value is not passed, rather the function

JavaScript: When assigning an anonymous function to a variable, function return value is not passed, rather the function


By : Joe
Date : March 29 2020, 07:55 AM
hope this fix your issue You need to call the function by passing it two arguments, because otherwise the z variable will just store a reference to this function but it will not evaluate it:
code :
var z = (function(x, y) {
    if ((y * (x / 100)) < 1) {
        return (x + Math.ceil(y * (x / 100))); }
    else if ((y * (x / 100)) > 1) {
        return (x + Math.round(y * (x / 100))); }
    else {
        return 0; 
    } 
})(x, y);
Why does 'this' return 'undefined' when referred in an arrow function but doesn't when called on an anonymous function?

Why does 'this' return 'undefined' when referred in an arrow function but doesn't when called on an anonymous function?


By : ashvin sanandia
Date : March 29 2020, 07:55 AM
I hope this helps you . Because arrow functions don't have their own this, they close over the this of the calling context. But non-arrow functions, if they're not bound, take this based on how they're called. I assume you're calling these functions like this:
code :
obj.getScopeWithArrow();
obj.getScopeWithAnonymous();
function showThis(label, t) {
  if (t === window) {
    console.log(label, "(global object)");
  } else {
    console.log(label, t);
  }
}
// Loose mode by default in a non-module script element
let obj = {
  arrow: () => {
    showThis("arrow says ", this);
  },
  normal: function() {
    showThis("normal says ", this);
  }
};
obj.arrow();  // global object (window on browsers)
obj.normal(); // obj

function foo() {
  // Here, we're in strict mode
  "use strict";
  let obj = {
    arrow: () => {
      showThis("arrow says ", this);
    },
    normal: function() {
      showThis("normal says ", this);
    }
  };
  obj.arrow();  // undefined
  obj.normal(); // obj

}
foo();
Call javascript function and obtain return value with anonymous function

Call javascript function and obtain return value with anonymous function


By : Erin Yoo
Date : March 29 2020, 07:55 AM
Hope this helps I saw some JavaScript calling function like this: , Are you looking for this?
code :
<script>
    function Calculate(a, b, callback) {
        var result = a + b;
        return callback(result);
    }

    function doIt2(a, b) {
        Calculate(a, b, function(data) {
            console.log(data);
        });
    }
</script>
<button onclick="doIt2(5,10);">Click</button>
Scopes and Closures - Return anonymous function inside another anonymous function?

Scopes and Closures - Return anonymous function inside another anonymous function?


By : Jobin
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Of course anonymous functions can return other functions. Functions are first-class-citizens in js. Every embedded function has access on the context of the enveloping function, except for the this property. You can use the context of the four forEach functions to store the number of increments. When you return something from withing an event listener, i dont know if this return is ever used somewhere. It maybe just exists the function.
code :
    var buttons = document.querySelectorAll("button");
    
    buttons.forEach(function(button){
      var increment = 0;
      button.addEventListener("click", function(event){
        increment++;
          alert("button " + event.currentTarget.innerHTML + ":" + " has been clicked " + increment + " times." );
         }
       );
    });
<button>1</button>
<button>2</button>
<button>3</button>
<button>4</button>
When returning an anonymous function from a function, is the function in the return statement a function declaration or

When returning an anonymous function from a function, is the function in the return statement a function declaration or


By : Patrick
Date : March 29 2020, 07:55 AM
With these it helps So I did some digging in the ECMAScript Language Specification and came to the conclusion that the anonymous function that's being returned is a function expression... and it really seems quite simple now. When defining a function using a function declaration, the identifier isn't optional and so an anonymous function can't be defined using a function declaration. Anonymous functions can only be defined using function expressions because with function expressions, the identifier is optional.
I also said this...
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