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How ASP MVC return json with variable name


How ASP MVC return json with variable name

By : Kahle
Date : November 22 2020, 11:17 AM
wish of those help In order to get exactly the same Json structure as you wanted, you will have to modify your User class to look like:
code :
public class User
{
    public string phone { get; set; }
    public string address { get; set; }
}
Dictionary<string, User> dictionary = new Dictionary<string, Controllers.User>();
        dictionary.Add("Chris", new User() { phone = "45096820", address = "xxx, street" });
        dictionary.Add("Jason", new User() { phone = "406980968", address = "xxx, street" });
        return Json(new { Users = dictionary }, JsonRequestBehavior.AllowGet);


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accessing the json return variable

accessing the json return variable


By : user2738583
Date : March 29 2020, 07:55 AM
seems to work fine Change your success function to accept a parameter and then you can refer to the returned data. i.e:
code :
function successFn(msg){
    alert(msg.d);
};
zf2 How to save json return value to a variable

zf2 How to save json return value to a variable


By : user3001535
Date : March 29 2020, 07:55 AM
I hope this helps . I assume you are returning the json array from a controller's action to a view file.
Was this action called via some ajax call? If yes then, on success of that ajax call, you will have something as -
code :
$.ajax({
    .....
    .....
    .....
    success: function(data) {
        var a = data.id;        //Here variable a will have value as 83493
    },
});
How do I get return value of a JSON object as a variable

How do I get return value of a JSON object as a variable


By : ajsv
Date : March 29 2020, 07:55 AM
will help you No need to regenerate the chart or have the update chart function in a separate timer. Just update the chart as and when you get data from relayr as follows:
code :
var yVal = 0, xVal = 0, dataLength = 500;
var dps = []; // dataPoints

var chart = new CanvasJS.Chart("chartContainer", {
    title: {
        text: "Westminster Cathedral Building Movement Data"
    },
    data: [{
        type: "line",
        dataPoints: dps
    }]
});
relayr.devices().getDeviceData({
    token: toke,
    deviceId: Candle1_deviceId,
    incomingData: function (data) {
        console.log(data.readings[0].meaning);
        console.log(data.readings[0].value);
        yVal = data.readings[0].value;
        dps.push({
            x: xVal,
            y: yVal
        });
        xVal++;

        if (dps.length > dataLength) {
            dps.shift();
        }
        chart.render()
        return data.readings[0].value;
    }
});
How to return json object by variable?

How to return json object by variable?


By : Henrik Bulskov
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You can do it with ES6's find easily,
code :
var textObj = JSON.parse(text)
var mail = textObj.products.find(itm => itm.name == c).mail
console.log(mail); // "john@mail.com"
Return a second variable in a JSON array

Return a second variable in a JSON array


By : John Randbrangers
Date : March 29 2020, 07:55 AM
wish help you to fix your issue When using .NET 4.0+ you can use a dynamic type to merge those two values into a new object and return that just like
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