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Javascript slide in slide out div


Javascript slide in slide out div

By : logix727
Date : November 22 2020, 11:17 AM
wish of those help Check this update: JS Fiddle updated! (http://jsfiddle.net/jPneT/2705/)
Uses 3 views you have a default view Easy methods to navigate.
code :
$(document).ready(function(){
    var currentPageI = -1;
    var pages = [
        $('div.l1'),
        $('div.l2'),
        $('div.l3'),
    ];
    var viewsWidth = 200; 
    var showPage = function(index){
        if(index === currentPageI){return;}
        var currentPage = pages[currentPageI];
        if(currentPage){
            currentPage.stop().animate({left: -viewsWidth})
        }
        var nextPage = pages[index];
        nextPage
            .stop()
            .css({left: viewsWidth})
            .animate({left: 0}) 
        currentPageI = index;
    }
    // show default page
    showPage(0);
    $('a.l1').click(showPage.bind(null, 0));
    $('a.l2').click(showPage.bind(null, 1));
    $('a.l3').click(showPage.bind(null, 2));

    $('.left-right').mouseover(function(){
        $('.slider').stop().animate({
            right: 0    
        }, 400);                        
    }).mouseout(function(){
        $('.slider').stop().animate({
            right: '-200px'    
        }, 400);     
    });

});
<a class="l1">1</a><a class="l2">2</a><a class="l3">3</a>

<div class="left-right">
    <div class="l1">L1 view</div>
    <div class="l2">L2 view</div>
    <div class="l3">L3 view</div>
</div>
.left-right {
    overflow:hidden;
    height:200px;
    width:200px;
    position:relative;
    background-color:#333;
    clear: left;
}
div.l1,div.l2,div.l3 {
    width:200px;
    height:200px;
    position:absolute;
    top:0;
    right:-200px;
    color:#fff;
}
a.l1,a.l2,a.l3 {
    display: block;
    width: 50px;
    height: 50px;
    float: left;
    cursor: pointer;
    opacity: 0.6;
}
a:hover {
    opacity: 1
}

.l1{
    color: red;
    background-color:red;
}
.l2{
    color: green;
    background-color:green;
}
.l3{
    color: blue;
    background-color:blue;
}


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How to use JQuery UI slide effect to seamlessly slide out one div and slide in another div?

How to use JQuery UI slide effect to seamlessly slide out one div and slide in another div?


By : JennyB
Date : March 29 2020, 07:55 AM
this one helps. It's because you're calling the effect on #viewPort2 in the callback to the effect of #viewPort. That means it will occur only once the effect on #viewPort has fully finished. Try calling the effect on #viewPort2 right after the one on #viewPort, for example:
code :
$( "#viewPort" ).effect( "slide", hideoptions, 1000); //notice, no callback
$( "#viewPort2" ).effect( "slide", showoptions, 1000);
How to get new slide to slide over previous slide in Bxslider?

How to get new slide to slide over previous slide in Bxslider?


By : user2809958
Date : March 29 2020, 07:55 AM
may help you . Bxslider itself is not designed to operate in that way. It only supports three types of transitions ("mode" in the API): fade, horizontal, and vertical. To support the behavior you want would require modifications to Bxslider.
Bxslider stores all the images in the slider in a ul element with a class "bxslider". It then uses the transform property to move the entire slider left/right (or up/down for a veritcal slider). To get the desired behavior you would have to modify bxslider to transform the individual images instead of the ul container.
code :
var setPositionProperty = function(value, type, duration, params){
    var selectedSlide=parseInt(slider.active.index) + 1;
    // Handle going backwards
    if(value==0)
        selectedSlide++;
    //By default, slide the entire container
    var selectedEl = el;
    //If set to use "lockedSlide", then only slide one image rather
    //than all of them
    if(slider.settings.lockedSlide===true)
        selectedEl = $(el.children()[selectedSlide-1]);

    // use CSS transform
    if(slider.usingCSS){
        // determine the translate3d value
        var propValue = slider.settings.mode == 'vertical' 
                        ? 'translate3d(0, ' + value + 'px, 0)' 
                        : 'translate3d(' + value + 'px, 0, 0)';
        // add the CSS transition-duration
        selectedEl.css('-' + slider.cssPrefix + '-transition-duration', duration / 1000 + 's');
        if(type == 'slide'){
            // set the property value
            selectedEl.css(slider.animProp, propValue);
            // bind a callback method - executes when CSS transition completes
            selectedEl.bind('transitionend webkitTransitionEnd oTransitionEnd MSTransitionEnd', function(){
                // unbind the callback
                el.unbind('transitionend webkitTransitionEnd oTransitionEnd MSTransitionEnd');
                updateAfterSlideTransition();
            });
        }else if(type == 'reset'){
            selectedEl.css(slider.animProp, propValue);
        }else if(type == 'ticker'){
            // make the transition use 'linear'
            selectedEl.css('-' + slider.cssPrefix + '-transition-timing-function', 'linear');
            selectedEl.css(slider.animProp, propValue);
            // bind a callback method - executes when CSS transition completes
            selectedEl.bind('transitionend webkitTransitionEnd oTransitionEnd MSTransitionEnd', function(){
                // unbind the callback
                selectedEl.unbind('transitionend webkitTransitionEnd oTransitionEnd MSTransitionEnd');
                // reset the position
                setPositionProperty(params['resetValue'], 'reset', 0);
                // start the loop again
                tickerLoop();
            });
        }
    // use JS animate
    }else{
        var animateObj = {};
        animateObj[slider.animProp] = value;
        if(type == 'slide'){
            selectedEl.animate(animateObj, duration, slider.settings.easing, function(){
                updateAfterSlideTransition();
            });
        }else if(type == 'reset'){
            selectedEl.css(slider.animProp, value)
        }else if(type == 'ticker'){
            selectedEl.animate(animateObj, speed, 'linear', function(){
                setPositionProperty(params['resetValue'], 'reset', 0);
                // run the recursive loop after animation
                tickerLoop();
            });
        }
    }
}
$('.bxslider').bxSlider({
  infiniteLoop: false,
  hideControlOnEnd: true,
  mode: 'horizontal',
  lockedSlide: true
});
Animate buttons (slide left, slide right, slide down) in unity3d v4.6

Animate buttons (slide left, slide right, slide down) in unity3d v4.6


By : Rosario Zúñiga Soto
Date : March 29 2020, 07:55 AM
Any of those help You can use iTween to do this:
code :
static float y0;
static float FadeInOutTime = 1.0f;

//Called in Awake()
y0 = GameObject.Find("button_home").transform.position.y;

public static IEnumerator AnimateIn ()
{
    int i = 0;

    foreach (var item in ToolbarButtons) {
        var pos = item.transform.position;
        iTween.MoveTo(item, new Vector3(pos.x, y0 + 6, pos.z), FadeInOutTime);
        yield return new WaitForSeconds (i * 0.02f);
        i++;
    }
    yield return null;
}
Creating a javascript slider; slide motion doesn't work on 1st slide, but sliding motion works after second slide?

Creating a javascript slider; slide motion doesn't work on 1st slide, but sliding motion works after second slide?


By : user44299
Date : March 29 2020, 07:55 AM
I wish this help you Reason it isn't working is because you have provided the initial state for it to transition from.
Simply adjust your css to this
code :
  .slider > ul {
   position: relative;
   transition: left .5s ease-in-out;
   left:0;
 }
Is there any Google Slide AppScript trigger function called when the presenter progresses from slide-to-slide?

Is there any Google Slide AppScript trigger function called when the presenter progresses from slide-to-slide?


By : Fady Khafaga
Date : March 29 2020, 07:55 AM
seems to work fine No, there isn't. Unfortunately Google Apps Script hasn't a built-in feature to implement custom-triggers.
Reference
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