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Find object in tree of objects


Find object in tree of objects

By : Yosra Maaref
Date : November 22 2020, 11:12 AM
wish of those help Hello i have a next object: , I think this is the answer:
code :
private Industry GetIndustryById(List<Industry> IndustryList, int? id)
{
    if (id != null)
    {
        foreach (Industry industry in IndustryList)
        {
            if (industry.id == id)
            {
                return industry;
            }
        }
        foreach (Industry industry in IndustryList)
        {
            if (industry.industryList != null)
            {
                // Here was your mistake. If you return GetIndustryById()
                // without checking for null first, you will return null
                // if that subtree doesn't contain the target, even if
                // a subsequent subtree does.

                var result = GetIndustryById(industry.industryList, id);

                if (result != null)
                    return result;
            }
        }
    }
    return null;
}


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Cannot find a Git object in its objects tree

Cannot find a Git object in its objects tree


By : amunn
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Yes, the database is occasionally packed.
Javascript: deep find object in tree, then return object and the path to it through the tree

Javascript: deep find object in tree, then return object and the path to it through the tree


By : Ajay Kumar
Date : March 29 2020, 07:55 AM
this one helps. So T.J. Crowders position ended up having a bug around recording the path, and I ended up tweaking the solution to get the following, which works excellently.
code :
  _findInTree(id, tree) {
    if (tree.id === id) {
      let path = [tree.name];
      return {result: tree, path};
    } else {
      for (let child of tree.children) {
        let tmp = this._findInTree(id, child);
        if (!_.isEmpty(tmp)) {
          tmp.path.unshift(tree.name);
          return tmp;
        }
      }
      return {};
    }
  }
beautifulsoup table tree: find all tr between two objects?

beautifulsoup table tree: find all tr between two objects?


By : sonert geass
Date : March 29 2020, 07:55 AM
wish of those help Option 1: find_next_siblings() and break when you meet a row with a GREEN BOX.
code :
red_box = soup.find("tr", text="RED BOX")
for row in red_box.find_next_siblings("tr"):
    if row.get_text(strip=True) == "GREEN BOX":
        break

    print([td.get_text(strip=True) for td in row.find_all("td")])
def filter_rows(tag):
    return tag.name == "tr" and \
           tag.find_previous_sibling("tr", text="RED BOX") and \
           tag.find_next_sibling("tr", text="GREEN BOX")

for row in soup.find_all(filter_rows):
    print([td.get_text(strip=True) for td in row.find_all("td")])
['ball 1', 'ball 2']
['ball 3']
green_box = soup.find("tr", text="GREEN BOX")
for row in green_box.find_next_siblings("tr"):
    print([td.get_text(strip=True) for td in row.find_all("td")])
Finding the objects in a tree of objects between the root and any object

Finding the objects in a tree of objects between the root and any object


By : rjorgenson
Date : March 29 2020, 07:55 AM
will be helpful for those in need The flaw with your code is that you are using a global (out of f's scope anyway) path array. The problem is that you are clearing the entire array if a node doesn't match, whereas you should only cut the current part out. There are two ways to achieve what you want: first is to make f accepts an array path that it copies and pass over recursively untill it find the object, and the other way which is the best approach is to make use of the call stack (created by the recursion):
code :
public getPath(tree: Array<object>, o: object): Array<object> {

    function f(subtree: Array<object>) {                              // I don't know typescript, so specify the return type as (Array<object> or null)
        for (let node of subtree) {
            if (node.data == o) {                                     // if this is the node we're looking for
                return [node];                                        // return an array (which will be our path), here you can either return [] to exclude the matched node (o) or [node] to include it
            } else if(node.subs.length) {                             // not the node we are looking for, but it has children, so let check'em out 
                let result = f(node.subs);                            // result will either be an array (if we recursively found something), or null otherwise
                if(result) {                                          // if we found something, then result will be the path from the current node to the object o (the current node not included)
                    result.unshift(node);                             // we include the current node by pushing it into the result array (pushing it to the first position)
                    return result;                                    // return result (an array) to signal successfulness
                }
            }
        }
        return null;                                                  // the object o not found in this subtree, return null to signal unsuccessfullness. Kind of redundant, because undefined is returned by default, so feel free to remove it
    }

    return f(tree);    
}
Two Trees: one Tree's nodes contains a List of objects; the 2nd Tree's objects contains references to the first Tree's o

Two Trees: one Tree's nodes contains a List of objects; the 2nd Tree's objects contains references to the first Tree's o


By : user3055995
Date : March 29 2020, 07:55 AM
it should still fix some issue Yes you can.
You declared Range as class (as opposed to struct), therefore you will only be handling references (as opposed to the actual values).
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