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Instantiating a class which has generic params?


Instantiating a class which has generic params?

By : Navvab Patricio
Date : November 22 2020, 11:05 AM
fixed the issue. Will look into that further @user3269829 you should not use HashMap for contain data of different types. You can add custom container, i.e. a class with three field:
code :
class Container<B extends Billing,E extends Employee, L extends Level> {

    B billing;

    E employee;

    L level;

    public Container(B b, E e, L l) {
        billing = b;
        employee = e;
        level = l;
    }

    // ... getters only!
}
 public void process(Container<B, E, L> input)
SomeRequest<Billing,Employee,Level> instance = new SomeRequest<>();
instance.setBilling(container.getBilling());
instance.setEmployee(container.getEmployee());
instance.setLevel(container.getLevel());
SomeRequest<Billing,Employee,Level> instance = new SomeRequest<>(container.getBilling(), container.getEmployee(), container.getLevel());


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How to document a Class and shows its constructor params when instantiating, using Netbeans autocomplete?

How to document a Class and shows its constructor params when instantiating, using Netbeans autocomplete?


By : Ruslan Ryzhkov
Date : March 29 2020, 07:55 AM
help you fix your problem The answer is: Netbeans only understand __construct() methods as class constructors.
You can document your class normally, and your constructor method normally, but using __construct().
Error when instantiating a generic class with a generic parameter

Error when instantiating a generic class with a generic parameter


By : junaid ahmad
Date : March 29 2020, 07:55 AM
seems to work fine You can strip the type parameter on the constructor and surpress the warning
code :
public JAXBSerializing(Class<?> oType)
{
    mType = oType;
}
IXMLSerializing<MapEntry<String, String>> serializer = new JAXBSerializing<MapEntry<String, String>>(MapEntry.class);
Instantiating generic class and implementing generic interface

Instantiating generic class and implementing generic interface


By : maanasa
Date : March 29 2020, 07:55 AM
I wish this helpful for you According to @JB Nizet's comment, I've solved the problem by creating two separate factory classes like this:
code :
public interface ItemFactory<E> {
    E create(int[] values);

    public static class DrawItemFactory implements ItemFactory<DrawItem> {

        @Override
        public DrawItem create(int[] values) {
            return new DrawItem(values);
        }           
    }

    public static class DrawNumberFactory implements ItemFactory<DrawNumber> {

        @Override
        public DrawNumber create(int[] values) {
            return new DrawNumber(values);
        }           
    }
}
public class CombinationGenerator<E> {
    ItemFactory<E> factory;

    public CombinationGenerator<E>(ItemFactory<E> factory) {
        this.factory = factory;
    }

    public List<E> generate() {
        ......
        list.add(factory.create(...));
        ......
    }
}
DrawNumber drawNumber = new DrawNumber();
CombinationGenerator<DrawNumber> generator = new CombinationGenerator<DrawNumber>(new ItemFactory.DrawNumberFactory());

List<DrawNumber> combinations = generator.generate();
What are rules governing instantiating instances of generic outer class and its inner generic inner class and declaring

What are rules governing instantiating instances of generic outer class and its inner generic inner class and declaring


By : M. Dennhardt
Date : March 29 2020, 07:55 AM
I wish this helpful for you The examples which don't compile are mostly examples of rare types. (Also, as noted by John in the comments, the obj3 example shouldn't compile either.)
A raw type is the type which is formed by using a generic type without an accompanying type argument list (like e.g. Set, as opposed to e.g. Set). A rare type is when you have a generic outer class and generic inner class, one of which is raw and the other is not.
code :
class Outer<T>{
    class Inner<S> {
        S s;
    }
}
Outer.Inner<Double> x = null;  // illegal
Double d = x.s;
Outer<Integer>.Inner x = null; // illegal
MyGen<String>.GenInner<Integer> ok1 = new MyGen<String>().new GenInner<Integer>();
MyGen<String>.GenInner<Integer> ok2 = new MyGen<String>().new GenInner<>();
Instantiating of a class derived from a generic one that has params in its constructor

Instantiating of a class derived from a generic one that has params in its constructor


By : Karim
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Constructors aren't inherited in C#. If you don't specify a constructor, the compiler will generate a parameterless constructor for you, which calls the base class's parameterless constructor. If your class derives from a base class which doesn't have any non-private parameterless constructors, the compiler errors.
So your plan of getting Bar to inherit the Foo constructor which takes a params T[] will never work.
code :
class Bar : Foo<int>
{
    public Bar(params int[] list) : base(list) { }
}
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