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How do object references work in JavaScript


How do object references work in JavaScript

By : crass
Date : November 22 2020, 11:05 AM
will help you
Does it only keep two pointers to the "HeavyObject" or is the reference done differently?
code :
var LightWheight = {
    property1: {
        sub_property: {
            property1: {}
            property2: 1,
            propertyN: false,
            func1: function () {}
            func2: function () {}....
            funcN: function () {}
        }
    },
    property2: {
        sub: {
            sub: {
                flag: true,
                heavy: property1: {}
                property2: 1,
                propertyN: false,
                func1: function () {}
                func2: function () {}....
                funcN: function () {}
            }
        }
    } }


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Why does this work? Object references in Javascript

Why does this work? Object references in Javascript


By : Loan_ID
Date : March 29 2020, 07:55 AM
it fixes the issue All variables in JavaScript are not objects. There are native types as well.
c and d are not linked to one another. They are pointing to the same object reference. If you were to reassign d to something else, it will not affect c.
code :
var c = {};
var d = c;
d = { foo: "bar" };

c === d // false
how do jQuery object references work?

how do jQuery object references work?


By : Vanessa Robitaille
Date : March 29 2020, 07:55 AM
I wish this help you There are no references. Anyway...
$(selector) returns a fixed set of elements that currently match the selector.
code :
x = $('.footer')
// if x.length == 0 then...
// a long time later, assuming x is not assigned to again...
// x.length == 0 is still true
How do object references work internally in javascript

How do object references work internally in javascript


By : jani
Date : March 29 2020, 07:55 AM
I wish this helpful for you Objects in Javascript are passed by reference. That is, only one object is created and the symbol that represents that object can be used but it will refer to the same object always.
Lets take a deeper look:
code :
var temp = {}
var arr = []

temp['a'] = ['a']
arr.push(temp)
console.log(arr);
[ { a: [ 'a' ] } ]
temp['b'] = ['b']
arr.push(temp);
console.log(arr);
[ { a: [ 'a' ], b: [ 'b' ] }, { a: [ 'a' ], b: [ 'b' ] } ]
temp = {};
temp['a'] = ['a']
temp['b'] = ['b']
arr.push(temp);
console.log(arr);
 [ { a: [ 'a' ] }, { a: [ 'a' ], b: [ 'b' ] } ]
I have a JavaScript parameter, which references an object. How to change the referenced object to a string, instead of c

I have a JavaScript parameter, which references an object. How to change the referenced object to a string, instead of c


By : echohao
Date : March 29 2020, 07:55 AM
I hope this helps . Your problem is, you assign a value to a local variable. To break it down:
You have an object, and a variable with an object reference.
code :
var test = { level0: { level1: 42 } },
    temp = test.level0;
temp = 'foo';
var test = { level0: { level1: 42 } },
    temp = test.level0;

console.log(temp); // { level1: 42 }
temp = 'foo';
console.log(temp); // 'foo'
console.log(test); // { level0: { level1: 42 } }
var test = { level0: { level1: { level2: 42 } } },
    key = 'level1',
    temp = test.level0;

temp[key] = 'bar';
console.log(temp); // { level1: 'bar' }
console.log(test); // { level0: { level1: 'bar' } }
function iter(object, key) {
    return Object.keys(object).forEach(function (k) {
        if (!object[k] || typeof object[k] !== 'object') {
            return;
        }
        if (key in object[k]) {
            object[k] = object[k][key];
            return;
        }
        iter(object[k], key);
    });
}


var object = { report: { title: { nl: "Rapportage", de: "Rapportage DE", en: "Rapportage EN" } }, searchmachine: { title: { nl: "Machine zoeken", de: "Machine zoeken DE", en: "Machine zoeken EN" }, Systeemnaam: { nl: "Systeemnaam", de: "Systeemnaam DE", en: "Systeemnaam EN" }, plaats: { nl: "plaats", de: "plaats DE", en: "plaats EN" }, macaddress: { nl: "macaddress", de: "macaddress DE", en: "macaddress EN" } } };

iter(object, "en");
console.log(object);
.as-console-wrapper { max-height: 100% !important; top: 0; }
References and How They Work in JavaScript

References and How They Work in JavaScript


By : user2682065
Date : March 29 2020, 07:55 AM
it fixes the issue The value type decides whether the assignment is by value (for primitive types like boolean, number etc) or by reference (object / array). So foobar itself doesn't have an address, it's just a pointer to the object's address. ref will point to the same object in memory (it will contain the same pointer to the address). So you could say they both point to 0x0B1EC7.
You can read more about it here.
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