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What is the fastest method to find duplicates from a collection


What is the fastest method to find duplicates from a collection

By : Srđan Lazić
Date : November 22 2020, 11:05 AM
I hope this helps . You can use a Set to determine whether entries are duplicate. Also, repeatedEntries might as well be a Set, since the keys are meaningless:
code :
Map<Integer, String> directory=new HashMap<Integer, String>();
Set<String> repeatedEntries=new HashSet<String>();
Set<String> seen = new HashSet<String>();

// ... initialize directory, then:

for(int j=1;j<=directory.size();j++){
    String val = directory.get(j);
    if (!seen.add(val)) {
        // if add failed, then val was already seen
        repeatedEntries.add(val);
    }
}
for (String val : directory.values()) {
    if (!seen.add(val)) {
        // if add failed, then val was already seen
        repeatedEntries.add(val);
    }
}


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What is the fastest method for checking for duplicates in python?

What is the fastest method for checking for duplicates in python?


By : hanson
Date : March 29 2020, 07:55 AM
this will help Using a dictionary seems ideal. , Yes, you should use a set.
code :
def set_way():
    my_set = set()
    my_set_add = my_set.add   # remember the method
    for ele in x:
        if ele not in my_set:
            my_set_add(ele)   # call the method directly
dict time : 1.896939858077399
set time : 1.8587076107880456
Fastest ways to find duplicates

Fastest ways to find duplicates


By : vivek
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The fastest, most general way to find duplicates is with a hash table. That gives essentially constant-time access (with just a little added overhead to handle hash collisions).
If the set of integers is sufficiently dense, you could alternatively use an array indexed by value, but this is only practical if the percentage of holes is sufficiently small.
C# - fastest way of comparing a collection against itself to find duplicates

C# - fastest way of comparing a collection against itself to find duplicates


By : adp
Date : March 29 2020, 07:55 AM
seems to work fine As others mentioned, the correct approach here would be to use the HashSet class.
code :
var hashSet = new HashSet<string>();

foreach (var obj in testList)
{
    if (!hashSet.Add(obj.TestValue))
    {
        obj.IsDuplicate = true;
    }
}
Matt
Bob
Alice
Claire
Matt DUPLICATE
Fastest algorithm to find 2nd biggest element in Max Heap (with duplicates)

Fastest algorithm to find 2nd biggest element in Max Heap (with duplicates)


By : user2192616
Date : March 29 2020, 07:55 AM
Hope this helps There is no way to do this with better time complexity than O(n). With the example data you give (4,4,4,4,4,4,4,3,4) the heap could for example be one of these two:
code :
             4                      4
           /   \                  /   \
         4       4              4       4
        / \     / \            / \     / \
       4   4   4   4          4   4   3   4
      / \                    / \
     4   3                  4   4
    heap              hashmap
                    key | value (=frequency)
       4           -----+-------------------
      /              4  |  8
     3               3  |  1
function insert(element):
    key = element.key
    if key not in hashmap:
        hashmap.set(key, new Array)
        heap.insert(key)
    arr = hashmap.get(key) # get a reference to the array
    arr.append(element) # add element to array, affecting the hashmap-stored value

function extract(): # remove max element
    if heap.size() == 0:
        return # No more data
    key = heap.peek() # look at root value
    arr = hashmap.get(key) # get a reference to the array
    element = arr.pop() # extract from array, affecting the hashmap-stored value
    if arr.length() == 0:
        heap.extract()
        hashmap.delete(key)
    return element

function peek(): # return element with max value
    if heap.size() == 0:
        return # No more data
    key = heap.peek() # look at root value
    arr = hashmap.get(key)
    element = arr[-1] # last element in array
    return element
key = max(heap.root.children())
Fastest way to find duplicates in a string without using any additional memory in java?

Fastest way to find duplicates in a string without using any additional memory in java?


By : LinkinNg
Date : March 29 2020, 07:55 AM
I wish this help you What is the fastest way to remove duplicate character in a string without using an extra memory in Java? , Use indexOf and delete methods in StringBuilder.
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