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how to create simple derived type from XSD


how to create simple derived type from XSD

By : Rameshwar Narwade
Date : November 22 2020, 11:02 AM
hope this fix your issue how to can I create derived simpleType in your XSD file BASED ON xs:ID. The restriction should use a pattern with a value that starts with a "_", followed by two characters that are digits in the range 1 - 8. , the redexp is _[1-8][1-8]
code :
 <xs:attribute name="postion">
                     <xs:simpleType>
                       <xs:restriction base="xs:ID">
                         <xs:pattern value="_[1-8][1-8]">
                       </xs:restriction>
                     </xs:simpleType>


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How to create a dynamic type derived from a closed generic type

How to create a dynamic type derived from a closed generic type


By : user3742914
Date : March 29 2020, 07:55 AM
will be helpful for those in need Shame on me.
As VirtualBlackFox stated my slightly condensed example works. In my "real" code I create the name of the dynamic type by combining the FullNames of the types that need to be combined. This obviously produces an invalid typename when used with generic types (I found out that e.g. [ is invalid, which makes sense if you think about it).
Can we create derived public type from private base type in .net?

Can we create derived public type from private base type in .net?


By : Nicolas Bottaro
Date : March 29 2020, 07:55 AM
it should still fix some issue You simply can't. .NET doesn't allow you to make a derived type more accessible than the base type. You'll have to expose the base type.
Note that if you only give it internal constructors, then other code won't be able to instantiate it or create their own derived types... what's the problem with exposing it at that point?
How many bytes does a derived type (in Fortran) occupy? Are the locations contiguous? And a pointer to a derived type?

How many bytes does a derived type (in Fortran) occupy? Are the locations contiguous? And a pointer to a derived type?


By : vivek
Date : March 29 2020, 07:55 AM
I hope this helps . 1) This is not covered by the fortran standard. real and integer do not have to be 4 bytes wide. To ensure that by specifying their precision. If you do not care about the numeric precision, but about the number of bytes, do it like this
code :
 !In Fortran 2008
 use iso_fortran_env

 or

 !In Fortran 95
 integer,parameter :: int32  = selected_int_kind(9)
 integer,parameter :: real32 = selected_real_kind(p=6,r=37)

 and

    TYPE :: node
       INTEGER(int32) :: int
       REAL(real32) :: REALfirst
       REAL(real32) :: REALsecond
    END TYPE
From vector of pointers to a base type, return first element of derived type, casted as derived type

From vector of pointers to a base type, return first element of derived type, casted as derived type


By : FAB
Date : March 29 2020, 07:55 AM
Hope that helps So I am working on a game engine of sorts, and I've been struggling with this issue for a while now. I'm not sure if it is a design issue, or I just don't have the necessary understanding of C++ , You may do something like:
code :
template <typename Derived>
Derived* getFirstElementOfType(const std::vector<BaseComponent*>& components)
{
    for (auto* component : components) {
         auto* p = dynamic_cast<Derived*>(component);
         if (p != nullptr) {
             return p;
         }
    }
    return nullptr;
}
template <typename Derived>
Derived* getFirstElementOfType(const std::vector<BaseComponent*>& components)
{
    auto it = std::find_if(components.begin(), components.end(),
        [](BaseComponent* component)
        {
            return dynamic_cast<Derived*>(component) != nullptr;
        });
    if (it != components.end()) {
        return static_cast<Derived*>(*it);
    }
    return nullptr;
}
BComponent* bComp = getFirstElementOfType<BComponent>(vectorOfComponents);
Allow derived type cast as parent type to return `object`, but using the derived type's method

Allow derived type cast as parent type to return `object`, but using the derived type's method


By : Olga.S
Date : March 29 2020, 07:55 AM
To fix the issue you can do There is a straight-forward way to do this with explicit implementation as you suspected. This is only available if you use an interface rather than an abstract class.
code :
public interface IFetcher {
    IEnumerable<object> Fetch();
}

public class Fetcher<T> : IFetcher  {
    private readonly Func<IEnumerable<T>> _fetcher;
    public Fetcher(Func<IEnumerable<T>> fetcher) { _fetcher = fetcher; }
    IEnumerable<object> IFetcher.Fetch() => Fetch().Cast<object>();
    public IEnumerable<T> Fetch() => _fetcher();
}
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