Call c function from python wouldn't work

Call c function from python wouldn't work

By : DK M
Date : November 21 2020, 04:03 PM
fixed the issue. Will look into that further I am almost sure that I did this once a year ago... Not it just wouldn't work. Weird. I must be making a minor mistake somewhere... Please help! , One way to export a symbol is via an option to the linker:
code :
cl testdll.c /LD /link /export:sum
#define TESTAPI __declspec(dllexport)
#define TESTAPI __declspec(dllimport)

/* declaration */
TESTAPI int sum(int a, int b);

/* definition */
int sum(int a, int b)
    sum @ 10 NONAME 
    sum_alias=sum @ 20
cl testdll.c testdll.def /LD
>>> from ctypes import *
>>> lib = cdll.testdll
>>> lib.sum_alias(1, 2)
>>> lib[10](1, 2)      
>>> lib[20](1, 2)
>>> from ctypes import *
>>> lib = cdll.testdll
>>> sorted(vars(lib))
['_FuncPtr', '_handle', '_name']
>>> lib.sum_alias(1, 2)
>>> sorted(vars(lib))
['_FuncPtr', '_handle', '_name', 'sum_alias']

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Why does this python function not work if I wrap it in a def() call?

Why does this python function not work if I wrap it in a def() call?

By : user3202614
Date : March 29 2020, 07:55 AM
I hope this helps you . "Wrapping" it into def, means that you are declaring your function to futher usage, so, in order to use it you need call it. In your case, just add duplicateDel()
code :
def duplicateDel():
    f1 = csv.reader(open('file1.csv', 'rb'))
    writer = csv.writer(open("file2.csv", "wb"))
    x = set()
    for row in f1:
        if row[3] not in x:
            x.add( row[3] )

Python 2.7.11:Why does a function call work for one function but not for another?

Python 2.7.11:Why does a function call work for one function but not for another?

By : user5421137
Date : March 29 2020, 07:55 AM
To fix the issue you can do I'm using Python 2.7.11 on Debian Linux. , print and return functions are different overall.
code :
def print_me(string):
    print string

def return_me(string):
    return string

So I've mad a hug command but I would like it so it wouldnt @ the person being hugged

So I've mad a hug command but I would like it so it wouldnt @ the person being hugged

By : user2843482
Date : March 29 2020, 07:55 AM
I wish this helpful for you Alright, so you want the second "awwww" to not happen, right? Is there a way you can compare two different message authors? Like making the "awwww" block conditional. As an example, making it so that instead of just replying with "awwww" to every message that mentions it, making it only reply with awww to a member other than itself mentioning it. Also, without a conditional statement like that, even just a message like "@CloudBot" will still cause the whole "aww" response.
Creating a generator in a Python function call - why does this work?

Creating a generator in a Python function call - why does this work?

By : user3121598
Date : March 29 2020, 07:55 AM
hope this fix your issue This is just how the syntax is explicitly defined, see the original PEP:
Function call doesnt work python

Function call doesnt work python

By : dataVoice Appdev
Date : March 29 2020, 07:55 AM
this one helps. You need to strip newlines from the end of your lines. Try call as isPalindrome(line.strip()).
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