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Copying dicts from csv to a new dict-python


Copying dicts from csv to a new dict-python

By : Collin Trenery
Date : November 21 2020, 07:35 AM
To fix this issue Just put them in a list and pass the list around.
Since you didn't show us your code, I can't show you how to change it, but I can show you with some fake code.
code :
with open(filename, 'rb') as f:
    things = []
    while True:
        thing = parser(f)
        if not thing:
            break
        things.append(thing)
with open(filename, 'rb') as f:
    things = list(iter(partial(parser, f), None))
with open(filename, 'rb') as f:
    reader = csv.DictReader(f)
    things = list(reader)
with mgf.read(mgf_file) as temp_read:
    reader = list(temp_read)
reader = []
with mgf.read(mgf_file) as temp_read:
    for thing in temp_read:
        reader.append(thing)


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dict of dicts python

dict of dicts python


By : Felipe Sampaio
Date : March 29 2020, 07:55 AM
hop of those help? I have a python dictionary consisting of other dictionaries like so (example): , The following seems to do the trick:
code :
def f(d):
    paths = []
    for key, value in d.items():
        if value is None:
            paths.append([key, value])
        else:
            internal_lists = f(value)
            for l in internal_lists:
                paths.append([key] + l)
    return paths
try:
    xxx
except:
    xxx
for key in f.keys():
How do I create a new dict of dicts from a dict with nested dicts in Python

How do I create a new dict of dicts from a dict with nested dicts in Python


By : Ankit R
Date : March 29 2020, 07:55 AM
I hope this helps you . I am starting with a dict received from an api , You can build the output with a recursive function:
code :
def transform(ob):
    if isinstance(ob, list):
        return [transform(v) for v in ob]
    elif not isinstance(ob, dict):
        return ob
    return [{'element_name': k, 'value': transform(v)}
            for k, v in ob.items()]

values = {'fields': transform(start_dict)}
>>> from pprint import pprint
>>> def transform(ob):
...     if isinstance(ob, list):
...         return [transform(v) for v in ob]
...     elif not isinstance(ob, dict):
...         return ob
...     return [{'element_name': k, 'value': transform(v)}
...             for k, v in ob.items()]
...
>>> start_dict = {
...     "a": 795,
...     "b": 1337,
...     "c": [
...         {
...             "d1": 2,
...             "d2": [
...                  {
...                       "e1": 4
...                  }
...         ]
...         }
...     ]
...     }
>>> pprint({'fields': transform(start_dict)})
{'fields': [{'element_name': 'a', 'value': 795},
            {'element_name': 'c',
             'value': [[{'element_name': 'd1', 'value': 2},
                        {'element_name': 'd2',
                         'value': [[{'element_name': 'e1', 'value': 4}]]}]]},
            {'element_name': 'b', 'value': 1337}]}
If dicts in python are mutable, why does editing a dict contained in a second dict not change the second dict?

If dicts in python are mutable, why does editing a dict contained in a second dict not change the second dict?


By : Bitan Paul
Date : March 29 2020, 07:55 AM
help you fix your problem Mutable names
The problem in your code is that strings are immutable: you cannot modify the string 'Bruce' into 'Bruce Wayne'. You replace it and the reference is gone. If you use a mutable object as value, you can achieve the desired result:
code :
class Person:
    def __init__(self, name):
        self.name = name

    def __repr__(self):
        return repr(self.name)


super_hero_names = {
    'Superman': Person('Clark Kent'),
    'Spiderman': Person('Peter Parker')
}

bruce = Person('Bruce')
batman = {'Batman': bruce}

super_hero_names.update(batman)

bruce.name = 'Bruce Wayne'

print(super_hero_names)
# {'Superman': 'Clark Kent', 'Spiderman': 'Peter Parker', 'Batman': 'Bruce Wayne'}
super_hero_names = {
    'Superman' => 'Clark Kent',
    'Spiderman' => 'Peter Parker'
}

batman = {'Batman' => 'Bruce'}

super_hero_names.update(batman)

batman['Batman'] << ' Wayne' # Mutates the string, doesn't replace it!

print(super_hero_names)
# {"Superman"=>"Clark Kent", "Spiderman"=>"Peter Parker", "Batman"=>"Bruce Wayne"}
How to create dict of dicts from list of dicts in python?

How to create dict of dicts from list of dicts in python?


By : user2411430
Date : March 29 2020, 07:55 AM
it helps some times What you asked and what you gave as an example are 2 different things.
Here is The expected result for your example:
code :
>>> simpleDic = { i : i*10 for i in range(5)}
>>> dicInList = [simpleDic]
>>> listInDic = {'single_key' : dicInList}
>>> print(simpleDic, dicInList, listInDic)
{0: 0, 1: 10, 2: 20, 3: 30, 4: 40}
[{0: 0, 1: 10, 2: 20, 3: 30, 4: 40}]
{'single_key': [{0: 0, 1: 10, 2: 20, 3: 30, 4: 40}]}
>>> dicInDic = {'single_key' : simpleDic}
>>> dicInDic
{'single_key': {0: 0, 1: 10, 2: 20, 3: 30, 4: 40}}
Check the values in complex dict of dicts with another dict of dicts and save it a third dictionary

Check the values in complex dict of dicts with another dict of dicts and save it a third dictionary


By : Sergey Kohno
Date : March 29 2020, 07:55 AM
This might help you This solution might be better done using some other method more succinctly. However, it accomplishes the desired result.
code :
from pprint import pprint

dict3 = dict()

dict1 = {'company1':[{'age':27,'weight':200,'name':'john'},{'age':23,'weight':180,'name':'peter'}],
         'company2':[{'age':30,'weight':190,'name':'sam'},{'age':32,'weight':210,'name':'clove'},{'age':21,'weight':170,'name':'steve'}],
         'company3':[{'age':36,'weight':175,'name':'shaun'},{'age':40,'weight':205,'name':'dany'},{'age':25,'weight':160,'name':'mark'}],
         'company4':[{'age':36,'weight':155,'name':'lina'},{'age':40,'weight':215,'name':'sammy'},{'age':25,'weight':190,'name':'matt'}]
        }

dict2 = {'company2':[{'age':30},{'age':45},{'age':52}],
         'company4':[{'age':43},{'age':67},{'age':22},{'age':34},{'age':42}]
        }

for company, array in dict1.items():
    if company not in dict2:
        dict3[company] = array
    else:
        # all the ages for this company in dict1
        ages = set(map(lambda x: x['age'], array))

        for dictref in dict2[company]:
            if dictref['age'] in ages:
                dict3[company] = array
                break
pprint(dict3)
{'company1': [{'age': 27, 'name': 'john', 'weight': 200},
              {'age': 23, 'name': 'peter', 'weight': 180}],
 'company2': [{'age': 30, 'name': 'sam', 'weight': 190},
              {'age': 32, 'name': 'clove', 'weight': 210},
              {'age': 21, 'name': 'steve', 'weight': 170}],
 'company3': [{'age': 36, 'name': 'shaun', 'weight': 175},
              {'age': 40, 'name': 'dany', 'weight': 205},
              {'age': 25, 'name': 'mark', 'weight': 160}]}
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