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How to store a list as a dictionary - python


How to store a list as a dictionary - python

By : YD PC Solutions
Date : November 21 2020, 07:35 AM
I wish this help you I know how to store in a list but how do I store these values as a dictionary instead? , Declaring a dictionary:
code :
dictionary = {}
dictionary[newkey] = newvalue
print (dictionary[newkey])
newvalue


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How to match keys in a dictionary with the elements in a list and store those key values to another dictionary in python

How to match keys in a dictionary with the elements in a list and store those key values to another dictionary in python


By : Hodophobia
Date : March 29 2020, 07:55 AM
like below fixes the issue I have a dictionary like this:
code :
list1 = ['the', 'of', 'Starbcks', 'in', 'share', 'for', '%', 'fiscal', '2007', 'growth', 'year', 'cents', 'earnings', 'a', 'company', '2,400', 'net', 'abot', 'range', 'stores', 'revene', 'sales', 'gidance', '``', "''", 'earnings', 'provides', 'wew', 'net']
d={'and': {'of': 0.6520996477975429, 'in': 0.12241083209661485, 'to': 0.7091938791256235}, 'of': {'and': 0.6520996477975429, 'to': 0.8975056783377765, 'in': -0.46306801953487436}, 'in': {'and': 0.12241083209661485, 'of': -0.46306801953487436, 'to': -0.0654517869126785}, 'to': {'and': 0.7091938791256235, 'of': 0.8975056783377765, 'in': -0.0654517869126785}}
new_d ={}
for k in list1:
    if k in d:
        new_d[k] = d[k]
print(new_d)
{'of': {'and': 0.6520996477975429, 'to': 0.8975056783377765, 'in': -0.46306801953487436}, 'in': {'and': 0.12241083209661485, 'of': -0.46306801953487436, 'to': -0.0654517869126785}}
new_d ={ k: d[k] for k in list1 if k in d}
temp_dict = dict((key,value) for key,value in d.iteritems() if key in set(list1))
from collections import OrderedDict
new_d = OrderedDict(((k,d[k]) if k in d else (k,0) for k in list1 ))
How to store dictionary and list in python config file?

How to store dictionary and list in python config file?


By : Manish
Date : March 29 2020, 07:55 AM
this one helps. ConfigParser will only ever give you those elements as strings, which you would then need to parse.
As an alternative, YAML is a good choice for configuration files, since it is easily human readable. Your file could look like this:
code :
DEFAULT:
    ADMIN: xyz
    SOMEDICT:
        v1: k1
        v2: k2
    SOMELIST:
        - v1
        - v2
import yaml
with open('config.yml') as c:
    config = yaml.load(c)
config['DEFAULT']['SOMEDICT']
Store dictionary with list values in csv using python

Store dictionary with list values in csv using python


By : Linkz57
Date : March 29 2020, 07:55 AM
To fix this issue This is my dictionary structure , If you can use a 3rd party library, this is trivial with Pandas:
code :
import pandas as pd

# construct dataframe from dictionary d
df = pd.DataFrame(list(d.items()), columns=['movie id', 'keyword'])

# export to csv
df.to_csv('file.csv', index=False)
import pickle

with open('d_file.pkl', 'wb') as fout:
    pickle.dump(d, fout, protocol=pickle.HIGHEST_PROTOCOL)

with open('d_file.pkl', 'rb') as fin:
    d = pickle.load(fin)
How to find list contents in dictionary and store it in another dictionary using Python

How to find list contents in dictionary and store it in another dictionary using Python


By : user3616223
Date : March 29 2020, 07:55 AM
This might help you , You can use dict comprehension like below
code :
a=[1,2,4]
d={1:"k",2:"r",3:"t",4:"y",5:"z"}

new_dict = {i:d.get(i) for i in a}
print(new_dict)
{1: 'k', 2: 'r', 4: 'y'}
List vs dictionary to store zeroes in python

List vs dictionary to store zeroes in python


By : thinc
Date : March 29 2020, 07:55 AM
wish help you to fix your issue The access and update once you have pre-allocated your sequence will be roughly the same.
Pick a data-structure that makes sense for your application. In this case I suggest a list because it more naturally fits "sequence indexed by integers"
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