Is overriding __del__() the best choice here?

Is overriding __del__() the best choice here?

By : hobbyist
Date : November 21 2020, 07:35 AM
hope this fix your issue Python uses garbage collection to manager memory, which means you do not have to delete anything. This class is fine:
code :
class Bond():
    def breakBond(self):
>>> some_list = [1,2,3]
>>> b = some_list
>>> del b   # destroys the list?
>>> b
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name 'b' is not defined
>>> some_list   # list is still there!
[1, 2, 3]
>>> c = some_list
>>> del some_list
>>> c        # list is still there!
[1, 2, 3]
>>> del c

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Overriding the Home button - how do I get rid of the choice?

Overriding the Home button - how do I get rid of the choice?

By : Advaita11
Date : March 29 2020, 07:55 AM
I hope this helps you . You can't permanently override the Home button without the user confirming it.
One argument for why this is the case is a security one. The Home button is the one way a user can be guaranteed to exit any application. If you could make the Home button launch your application instead of the Home screen without the user confirming this change, it would then be very easy to write a malicious application that hijacked a user's phone.
MySql - Aggregate function for choosing first choice, second choice, third choice, etc?

MySql - Aggregate function for choosing first choice, second choice, third choice, etc?

By : Narasimha
Date : March 29 2020, 07:55 AM
should help you out The fastest solution I've found which gives the resultset I'm after is described in this article:
How to use __del__ in a reliable way?

How to use __del__ in a reliable way?

By : Erol BAŞAK
Date : March 29 2020, 07:55 AM
Any of those help In short: No, there is no way to ensure it gets called.
The answer is to implement context managers yourself. A with statement roughly translates to:
code :
Use cases for __del__

Use cases for __del__

By : sufyanali
Date : March 29 2020, 07:55 AM
it helps some times Context managers (and try/finally blocks) are somewhat more restrictive than __del__. In general they require you to structure your code in such a way that the lifetime of the resource you need to free doesn't extend beyond a single function call at some level in the call stack, rather than, say, binding it to the lifetime of a class instance that could be destroyed at unpredictable times and places. It's usually a good thing to restrict the lifetime of resources to one scope, but there sometimes edge cases where this pattern is an awkward fit.
The only case where I've used __del__ (aside from for debugging, c.f. @MSeifert's answer) is for freeing memory allocated outside of Python by an external library. Because of the design of the library I was wrapping, it was difficult to avoid having a large number of objects that held pointers to heap-allocated memory. Using a __del__ method to free the pointers was the easiest way to do cleanup, since it would have been impractical to enclose the lifespan of each instance inside a context manager.
__del__ at program end

__del__ at program end

By : Hari Gnanaprakasam
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further There are many potential difficulties associated with using __del__. Usually, it is not necessary, or the best idea to define it yourself.
Instead, if you want an object that cleans up after itself upon exit or an exception, use a context manager:
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