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Search XML (XPATH/XSLT) return a path in terms of 'rank'


Search XML (XPATH/XSLT) return a path in terms of 'rank'

By : M.Piedmont
Date : November 18 2020, 03:46 PM
I wish did fix the issue. I want to search XML and return the number of the returned search. For example; searching for 'orange' in the following list , I want to get back 6. , This stylesheet:
code :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    version="1.0">

    <xsl:template match="/">
        <xsl:variable name="position">
            <xsl:apply-templates select="fruits/name"/>
        </xsl:variable>

        <result><xsl:value-of select="$position"/></result>
    </xsl:template>

    <xsl:template match="name">
        <xsl:if test="text() = 'orange'">
            <xsl:value-of select="position()"/>
        </xsl:if>
    </xsl:template>

</xsl:stylesheet>
<result>6</result>


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XSLT-XPath: For-each path specification for re-grouping of elements

XSLT-XPath: For-each path specification for re-grouping of elements


By : Zobayer Ahmed
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have XML documents which I want to transfer into another structure. An example of a document looks as follows: , Your XPath expression was almost correct:
code :
<xsl:for-each 
    select="/application/contactPerson/countryCode[not(.=preceding-sibling::*)]"> 
<xsl:for-each 
    select="/application/contactPerson/countryCode[not(. = ../preceding-sibling::*/countryCode)]"> 
<xsl:template match="/">
    <application>
      <xsl:for-each select="/application/contactPerson/countryCode[not(.=../preceding-sibling::*/countryCode)]">
        <memberState>
          <countryCode>
            <xsl:value-of select="."/>
          </countryCode>
          <xsl:for-each select="/application/contactPerson[countryCode = current()]">
          <contactPerson>
            <name>
              <xsl:value-of select="name"/>
            </name>
          </contactPerson>
          </xsl:for-each>
        </memberState>
      </xsl:for-each>
    </application>
  </xsl:template>
MySQL Fulltext rank rows higher if keyword exists, but not part of the search terms

MySQL Fulltext rank rows higher if keyword exists, but not part of the search terms


By : Canuck1970
Date : March 29 2020, 07:55 AM
will help you You could try using +test cheese. Documentation states that the results must contain test but if they also contain cheese they are ranked higher.
An example query:
code :
SELECT 
  MATCH (name) AGAINST ('+test cheese' IN BOOLEAN MODE) AS relevance, 
  t.* 
FROM 
  test AS t 
WHERE 
  MATCH (name) AGAINST ('+test' IN BOOLEAN MODE) 
ORDER BY relevance DESC;
Xslt - How do you check for a grandchild node with a certain path name. (xpath 1.0)

Xslt - How do you check for a grandchild node with a certain path name. (xpath 1.0)


By : vamshi
Date : March 29 2020, 07:55 AM
will be helpful for those in need Do you really want to check whether the element names contain those strings? Or, as your narrative says, do you want elements with that exact name?
To do something like what you have already written, use
code :
<xsl:for-each select="*[contains(name(), 'description')]/*[contains(name(), 'text')]">
  <xsl:value-of select="node()"/>
</xsl:for-each>
<xsl:for-each select="description/text">
  <xsl:value-of select="node()"/>
</xsl:for-each>
<leaf>
  <description>
    <text>Various Words</text>
  </description>
  <description>
    <text>More Words</text>
  </description>
  <description>
    <text>Other Words</text>
  </description>
</leaf>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="text"/>

  <xsl:template match="/leaf">
    <xsl:for-each select="description/text">
      <xsl:value-of select="."/>
    </xsl:for-each>
  </xsl:template>

</xsl:stylesheet>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="text"/>

  <xsl:template match="/leaf">
    <xsl:apply-templates select="description/text"/>
  </xsl:template>

  <xsl:template match="text">
    <xsl:value-of select="."/>
  </xsl:template>

</xsl:stylesheet>
Creating an incremental count variable in XSLT / XPath when using Xpath for..in..return?

Creating an incremental count variable in XSLT / XPath when using Xpath for..in..return?


By : Javier Conte Alcaraz
Date : March 29 2020, 07:55 AM
this will help The following requires no additional namespaces. The solution contains a template called iterate that is called from within itself and which updates $length and $i accordingly:
XSLT
code :
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="/">
        <root>
            <xsl:call-template name="iterate"/>
        </root>
    </xsl:template>
    <xsl:template name="iterate">
        <xsl:param name="length" select="5"/>
        <xsl:param name="i" select="1"/>
        <pos><xsl:value-of select="$i"/></pos>
        <xsl:if test="$length > 1">
            <xsl:call-template name="iterate">
                <xsl:with-param name="length" select="$length - 1"/>
                <xsl:with-param name="i" select="$i + 1"/>
            </xsl:call-template>
        </xsl:if>
    </xsl:template>
</xsl:stylesheet>
<?xml version="1.0" encoding="UTF-8"?>
<root>
    <pos>1</pos>
    <pos>2</pos>
    <pos>3</pos>
    <pos>4</pos>
    <pos>5</pos>
</root>
Better performance with XPath Axes Vs Location Path Expression in XSLT/Xpath

Better performance with XPath Axes Vs Location Path Expression in XSLT/Xpath


By : CodeRed
Date : March 29 2020, 07:55 AM
will help you They are identical. Most axes can be selected only using the full form, but there are abbreviations for the most common ones that make an XPath expression more concise.
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